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dimaraw [331]
3 years ago
7

1,034 / 95 as a mixed number

Mathematics
1 answer:
tia_tia [17]3 years ago
7 0

Answer:

10 and 84/95

Step-by-step explanation:

First, you divide 1034 by 95 to see how many times it fits in there. Then, after it comes out to a ten with a lot of decimal points, you multiply 95 times 10, and then subtract the product from 1034 to see what the leftover fraction is. 95×10=950. 1034-950=84. Then, you look at 84/95 and see if it can be simplified-which it can't, so your final answer is 10  84/95.

(hope this helps, sry if its badly written)

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A local company has K2,500 to set up an annuity to be paid quarterly for 5 years. The payments of that annuity are to be increas
Anvisha [2.4K]

Answer:

Step-by-step explanation:

(a).

Within 1 year, there would be 4 payments to be made.

therefore, PMT= \frac{P(1+i)}{n} = \frac{2500(1+0.025)}{4*5} =\frac{2562.5}{20} = $128.125

(i) 1st payment will be :PMT $128.125

(ii) 2nd payment will be :128.125*(1.025)^1= $131.33

(iii) 3rd payment will be :128.125*(1.025)^2=$134.61

(iv) 4th payment will be :128.125*(1.025)^3=$137.98

Hence the payments are: $128.125, $131.33, $134.61, and $137.98.

(b).

The size of the final payment PMT(1+i)^{m-1} where m 4 *5= 20

=128.125(1+0.025)^{20-1} \\=128.125(1.025)^{19} \\=$204.83

3 0
1 year ago
Mr. Jacob arrived at his school at 07:10 and left at 15:45. How long was he in his school?
Makovka662 [10]

Answer:

he stayed 8 hours and 35 minutes

Step-by-step explanation:

15 -7 =8

45-10=35

7 0
2 years ago
Samantha is studying the population growth of an endangered birth. The growth can be modeled by the equation B(t) 100 + 3/5t^5 ,
solong [7]

The value of the population of the growth of an endangered birth after 5 years is 1975

<h3>How to determine the population after 5 years?</h3>

The population function is given as:

B(t) = 100 + 3/5t^5

At 5 years, the value of t is 5

So, we have

t = 5

Next, we substitute 5 for t in the equation B(t) = 100 + 3/5t^5

This gives

B(5) = 100 + 3/5 * 5^5

Evaluate the exponent

B(5) = 100 + 3/5 * 3125

Evaluate the product

B(5) = 100 + 1875

Evaluate the sum

B(5) = 1975

Hence, the value of the population of the growth of an endangered birth after 5 years is 1975

Read more about exponential functions at:

brainly.com/question/2456547

#SPJ1

4 0
1 year ago
Pls help find the amount at the end of 6 hours
marshall27 [118]

Answer:

A. 7,348

Step-by-step explanation:

P = le^kt

intitial population = 500

time = 4 hrs

end population = 3,000

So we have all these variables and we need to solve for what the end population will be if we change the time to 6 hours. First, we need to find the rate of the growth(k) so we can plug it back in. The given formula shows a exponencial growth formula. (A = Pe^rt) A is end amount, P is start amount, e is a constant that you can probably find on your graphing calculator, r is the rate, and t is time.

A = Pe^rt

3,000 = 500e^r4

now we can solve for r

divide both sides by 500

6 = e^r4

now because the variable is in the exponent, we have to use a log

log_{e}(6) = 4r

ln(6) = 4r

we can plug the log into a calculator to get

1.79 = 4r

divide both sides by 4

r = .448

now lets plug it back in

A = 500e^(.448)(6 hrs)

A = 7351.12

This is closest to answer A. 7,348

4 0
3 years ago
What is the value of y in the equation 9 + y = 8? this is extremely time sensitive
adoni [48]

You have to switch the 8 to the left and the y to the right which would change the equation to 9-8=y

y=1

5 0
3 years ago
Read 2 more answers
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