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3 years ago

1,034 / 95 as a mixed number

Mathematics

1 answer:

tia_tia [17]3 years ago

7 0

Answer:

10 and 84/95

Step-by-step explanation:

First, you divide 1034 by 95 to see how many times it fits in there. Then, after it comes out to a ten with a lot of decimal points, you multiply 95 times 10, and then subtract the product from 1034 to see what the leftover fraction is. 95×10=950. 1034-950=84. Then, you look at 84/95 and see if it can be simplified-which it can't, so your final answer is 10 84/95.

(hope this helps, sry if its badly written)

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(100 POINTS)

Sav [38]

Answer:

1. $\frac{7^8}{7^6}=49$

2. 7

3. 18

Step-by-step explanation:

Question 1:

Given:

The expression to simplify is $\frac{7^8}{7^6}$ .

We use the property of exponent $\frac{a^m}{a^n}=a^{m-n}$

Therefore, $\frac{7^8}{7^6}=7^{8-6}=7^2=7\times 7 = 49$

Question 2:

Given:

The expression to simplify is $7(\frac{1}{2}+\frac{1}{2})$ .

We add the fractions first inside the parenthesis.

So, $\frac{1}{2}+\frac{1}{2}=\frac{1+1}{2}=\frac{2}{2}=1$

Now, $7(1)=7$

Question 3:

The first five prime numbers are 1, 2, 3, 5, and 7.

Therefore, the sum of these five numbers is given as:

$1+2+3+5+7=18$

5 0

3 years ago

Read 2 more answers

HELP WILL MARK YOU BRAINLIEST!!!

Vlad [161]

Answer:

<PQR=132°

plz mark me brainliest

3 0

3 years ago

Q4) Using Euclid's algorithm, find the HCF of 240 and 228

Free_Kalibri [48]

$\LARGE{ \underline{ \boxed{ \purple{ \rm{Solution : )}}}}}$

Euclid's division lemma : Let a and b are two positive integers. There exist unique integers q and r such that

a = bq + r, 0 $\leqslant$ r < b

Or We can write it as,

Dividend = Divisor × Quotient + Remainder

Work out:

Given integers are 240 and 228. Clearly 240 > 228. Applying Euclid's division lemma to 240 and 228,

⇛ 240 = 228 × 1 + 12

Since, the remainder 12 ≠ 0. So, we apply the division dilemma to the division 228 and remainder 12,

⇛ 228 = 12 × 19 + 0

The remainder at this stage is 0. So, the divider at this stage or the remainder at the previous age i.e 12

$\large{ \therefore{ \boxed{ \sf{HCF \: of \: 240 \: \& \: 228 = 12}}}}$

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8 0

3 years ago

Donalita ate 5 out of every 7 candies in a jar. If she ate 25 candies, what fraction represents the number of candies she ate ov

kari74 [83]

Answer:

25/35

Step-by-step explanation:

5 times 7 equals 35 and that means that this is the denominator because that is our total amount.

5 times 5 equals 25 and that makes it the numerator because that is what is being taken out of 5 jars

Hopefully this helps you :)

4 0

3 years ago

Solve this and get 30 points !!!!!

jasenka [17]

First of all, don't let "b" confuse you. Know that b = 5/6k = -10, so all you really have to solve for this problem is $\frac{5}{6}k = -10$ .

Before anything else, you have to isolate k. Do this my multiplying both sides by the reciprocal of 5/6.

$\frac{6}{5} * \frac{5}{6}k = -10 * \frac{6}{5}$

The 6/5 and 5/6 cancel each other out, so we are left with $k = -10 * \frac{6}{5}$

--> $k = \frac{-10 * 60}{5}$

---> $\frac{-60}{5} = -12$

So k = -12.

Hope this helped. Good luck.

3 0

4 years ago