I am sure it is
$20 ÷ 3
But solving it....
5x^2-8x+5=0
ax^2+bx+c=0; a=5, b=-8, c=5
Quadratic Formula:
x=[-b+-sqrt(b^2-4ac)]/(2a)
x=[-(-8)+-sqrt( (-8)^2-4(5)(5) )] / [(2)(5) ]
x=[ 8+-sqrt(64-100)] / 10
x=[ 8+-sqrt(-36)] / 10
x=[8+-sqrt( (36)*(-1)) ] /10
x=[8+-sqrt(36)*sqrt(-1)] / 10
x=(8+-6i) / 10
x=(8/2+-6i/2) / (10/2)
x=(4+-3i)/5
x1=(4-3i)/5
x2=(4+3i)/5
Answers:
x=(4-3i)/5 , x=(4+3i)/5
12y = -18x -4x
12y = -22 x
x int = (12,0) when y is zero
y int = (0, -22) when x is zero
Equal length or equal degree for each vertex of the triangle
