5.5.35 Write the equation in standard form using integers. y= -3/7x - 7 The equation in standard form is
1 answer:
You might be interested in
The radical equation is 
.
i) We first isolate the square root, adding 5 to both sides of the equation:
ii) Here let's substitute x+6 with t. Doing so we have:
Squaring both sides, we get:
iii) Collecting the variables on the same side, and factorizing t we have:
, which yields
t=0 or t=1.
Now we solve for x in x+6=t:
x+6=0 ⇒x=-6 and x+6=1⇒x=-5.
iv) Now we check these values in the original equation
:
a)
⇒ 0=0 ; Correct.
b)
⇒ 1=1 ; Correct.
Answer: <span>x = −6 and x = −5 </span>
i) We first isolate the square root, adding 5 to both sides of the equation:
ii) Here let's substitute x+6 with t. Doing so we have:
Squaring both sides, we get:
iii) Collecting the variables on the same side, and factorizing t we have:
t=0 or t=1.
Now we solve for x in x+6=t:
x+6=0 ⇒x=-6 and x+6=1⇒x=-5.
iv) Now we check these values in the original equation
a)
b)
Answer: <span>x = −6 and x = −5 </span>
Answer:
Step-by-step explanation:
First of all you have to put the zeros into factor form.
y1 = (x + 2)(x - 5)
Notice that the x changes sigh. You say that the zeros are -2 and 5. To get y1 to go to zero, you must make x the opposite sign of what you are given.
Now you have to expand the factored form to get the standard form
y = x^2 + 2x - 5x - 10
y = x^2 - 3x - 10
That's not the right answer.
f(0) = 30 but you have - 10 at the end so you have to multiply the factored form by - 3
-3(f(x)) = -3(x + 2)(x - 5)
-3(f(x)) = -3(x^2 - 3x - 10)
f(x) = -3x^2 + 9x + 30
f(0) = -3(0)^2 + 9(0) + 30
f(0) = 30
The quadratic still has roots of (x +2)(x - 5) but that 3 makes the y intercept = 30.
See the graph below.
