Answer:
2
Step-by-step explanation:
Since triangle BDE is right, we can check it for special rules: BD is hypotenuse = 20, and BE = 12, both divisible by 4: get 5 and 3... so it's a 3-4-5 special right triangle, the 4×4 = 16 m for side DE.
Since AD bisects angle A, I think then side DG should be congruent with DG. So then
DG = 16 m
Q1. The answer is 4(2x - 3)(2x + 1)
16x² – 16x – 12 = 4 * 4x² - 4 * 4x - 4 * 3 =
= 4(4x² - 4x - 3) =
= 4(4x² + 2x - 6x - 3) =
= 4(2x * 2x + 2x - (2x * 3 + 3)) =
= 4(2x(2x + 1) - (3(2x + 1))) =
= 4((2x + 1)(2x - 3)) =
= 4(2x - 3)(2x + 1)
Q2. The answer is 3(x + 8)(x - 1)
3x² + 21x – 24 = 3 * x² + 3 * 7x - 3 * 8 =
= 3(x² + 7x - 8) =
= 3(x *x - x + 8x - 8) =
= 3((x(x - 1) + 8(x - 1)) =
= 3(x + 8)(x - 1)
There are different types of equations of lines.
There are these three main forms, but I'll focus on just 2:
Slope-Intercept Form:
y = mx + b
Where,
"m" = slope
"b" = y-intercept
Point-Slope Form:
y - y1 = m(x - x1)
Where,
"m" = slope
"y1" = A y point on the graph
"x1" = A x point on the graph that correlates with the y value.
y = 6x - 12
Is in the same form of Slope-Intercept:
So,
y = 6x - 12
m = 6
b = -12
So our slope is,
6
Keep in mind if it was a fraction (Example: 6/5, then the slope is 6/5) the slope will be the entire fraction.
Also remember slope is the RISE over the RUN meaning it is the y value over the x value. So in this case we would go UP 6 and right 1 (because 6 is understood as 6/1).
