2 years ago

Given cos 0= -1/2 and angle 0 is in quadrant two what is the exact value of sin 0 in simplest form

Mathematics

2 answers:

nignag [31]2 years ago

5 0

$\sin( \theta) = \frac{ \sqrt{3} }{2}$

Viktor [21]2 years ago

4 0

Answer:

$-\sqrt{7/4}$

Step-by-step explanation:

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Solve for x: 6x + 1 over 4 (4x + 8) > 12

sukhopar [10]

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Step-by-step explanation:

We have been given an inequality $6x+\frac{1}{4}(4x+8)>12$ . We are asked to solve the given inequality for x.

Using distributive property, we will get:

$6x+\frac{1}{4}*4x+\frac{1}{4}*8>12$

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Subtract 2 from both sides:

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$x>\frac{10}{7}$

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Only two of them are the correct answers to this question.

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Given cos 0= -1/2 and angle 0 is in quadrant two what is the exact value of sin 0 ￼ in simplest form￼

Given cos 0= -1/2 and angle 0 is in quadrant two what is the exact value of sin 0 in simplest form