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kupik [55]
2 years ago
5

Mrs. Miller has a rectangular garden with a length of 20 feet long with an area of (20x-200) square feet. Write an expression th

at represents the perimeter (in feet) of mrs. Miller‘s garden
Mathematics
1 answer:
krek1111 [17]2 years ago
6 0

Perimeter = (20 + 2x) mm.

Step-by-step explanation:

The octopus pupil has length 20 mm and the expression for its area is given by (20x - 200) square mm.

If the width of the octopus pupil is w, then 20w = 20x - 200

⇒ w = (x - 10) mm.

Therefore, the expression for its perimeter is 2(Length + Width) = 2 ( 20 + x - 10) = 2( 10 + x) = (20 + 2x) mm. (Answer)

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2 years ago
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The lateral area of a cylinder is 325 pi inch^2. The radius is 13 in. Find the surface area and volume. Please show all work!!!
USPshnik [31]
Answer:

Surface area =  663π in².
Volume = (676/3)π in² ≈ 225.33 π in²

Explanation:


1) We know the radius and the lateral area.

2) With the radius you can find the areas of the top and the bottom.

For that, you use the formula: 

area of the top = area of the bottom = π r² 


∴ π (13 in)² = 169π in² (each)


3) Then, the surface area is the sum of the lateral area and the two bases (top and bottom)

surface area = lateral area + bottom area + top area = 325π in² + 2×169π in² = 663π in².

3) You  can also find the height of the cylinder.

Use the formula: lateral area = 2π r h


∴ h = lateral area / [2 π r]

⇒ h = 325 π / [ 2π (13) ] = 12.5 in


4) With  the height you can find the volume.

Use the formula: V = (4/3) π r³ 

∴ V = (4/3) π (13 in)³ = (676/3)π in² ≈ 225.33 π in²
8 0
3 years ago
a store is selling cookies for $8.00 for 12 bags. how much will it cost if you want to buy 30 for your class
andrey2020 [161]

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olasank [31]
Answer is define variable
6 0
1 year ago
1. Given points A(3, -5) and B(19, -1), find the coordinates of point C that sit 3/8 of the way along line AB, closer to A than
zaharov [31]

1. C(x, y) = (7.3, –3.9)

2. C(x, y) = (17, –1.5)

Solution:

Question 1:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction \frac{3}{8}.

Point divides segment in the ratio formula:

$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)

Here, x_1=3, y_1=-5, x_2=19, y_2=-1 and m = 3, n = 8

$C(x, y)=\left(\frac{3\times19+8\times3}{3+8} , \frac{3\times(-1)+8\times(-5)}{3+8}\right)

           $=\left(\frac{57+24}{11} , \frac{-3-40}{11}\right)

           $=\left(\frac{81}{11} , \frac{-43}{11}\right)

C(x, y) = (7.3, –3.9)

Question 2:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction \frac{3}{8}.

Point divides segment in the ratio formula:

$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)

Here, x_1=3, y_1=-5, x_2=19, y_2=-1 and m = 7, n = 1

$C(x, y)=\left(\frac{7\times19+1\times3}{7+1} , \frac{7\times(-1)+1\times(-5)}{7+1}\right)

           $=\left(\frac{133+3}{8} , \frac{-7-5}{8}\right)

           $=\left(\frac{136}{8} , \frac{-12}{8}\right)

C(x, y) = (17, –1.5)

8 0
3 years ago
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