Ask question

Ask question

All categories

3 years ago

13

PLEASE HELP :)

2 answers:

Gnom [1K]3 years ago

5 0

Answer:

Math can help us do many things that are important in our everyday lives. ... As a parent, you could talk to your teen about how you use math in your daily life. You ... Share with your child the examples of everyday math applications, which are listed ... Your teen will learn skills in algebra class that will help them with money.

Step-by-step explanation:

Colt1911 [192]3 years ago

4 0

Math can help you if you ever wanna build a desk in the future;)

You might be interested in

What is 300 divided by 400

Anna35 [415]

Answer:

0.75

Step-by-step explanation:

300 out of 400 is the same as 3/4.

3/4 converted to a decimal is 0.75.

8 0

4 years ago

There are two square roots of 25. Which best explains why there is only one answer for the radius of the button?

Brrunno [24]

5 times5 is the one 5 times itself is 25 hents 25

4 0

3 years ago

Answer choices <br> a. -4/3 <br> b. -3/4 <br> c. 3/4<br> d. 4/3

Bingel [31]

Answer:

Step-by-step explanation:

(0, 1) (4, -2)

(-2 - 1)/(4 -0) = -3/4

7 0

3 years ago

Suppose that a spherical droplet of liquid evaporates at a rate that is proportional to its surface area: where V = volume (mm3

Alex

Answer:

V = 20.2969 mm^3 @ t = 10

r = 1.692 mm @ t = 10

Step-by-step explanation:

The solution to the first order ordinary differential equation:

$\frac{dV}{dt} = -kA$

Using Euler's method

$\frac{dVi}{dt} = -k *4pi*r^2_{i} = -k *4pi*(\frac {3 V_{i} }{4pi})^(2/3)\\ V_{i+1} = V'_{i} *h + V_{i} \\$

Where initial droplet volume is:

$V(0) = \frac{4pi}{3} * r(0)^3 = \frac{4pi}{3} * 2.5^3 = 65.45 mm^3$

Hence, the iterative solution will be as next:

i = 1, ti = 0, Vi = 65.45

$V'_{i} = -k *4pi*(\frac{3*65.45}{4pi})^(2/3) = -6.283\\V_{i+1} = 65.45-6.283*0.25 = 63.88$

i = 2, ti = 0.5, Vi = 63.88

$V'_{i} = -k *4pi*(\frac{3*63.88}{4pi})^(2/3) = -6.182\\V_{i+1} = 63.88-6.182*0.25 = 62.33$

i = 3, ti = 1, Vi = 62.33

$V'_{i} = -k *4pi*(\frac{3*62.33}{4pi})^(2/3) = -6.082\\V_{i+1} = 62.33-6.082*0.25 = 60.813$

We compute the next iterations in MATLAB (see attachment)

Volume @ t = 10 is = 20.2969

The droplet radius at t=10 mins

$r(10) = (\frac{3*20.2969}{4pi})^(2/3) = 1.692 mm\\$

The average change of droplet radius with time is:

Δr/Δt = $\frac{r(10) - r(0)}{10-0} = \frac{1.692 - 2.5}{10} = -0.0808 mm/min$

The value of the evaporation rate is close the value of k = 0.08 mm/min

Hence, the results are accurate and consistent!

5 0

3 years ago

Find the area of the figure. If necessary, round to the nearest tenth.

nirvana33 [79]

Answer:9.4cm2

Step-by-step explanation:

8 0

3 years ago