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Alina [70]
2 years ago
13

Is it Y-axis or X-axis I need by 11:30

Mathematics
2 answers:
Savatey [412]2 years ago
8 0
I believe it is y axis that it is reflected by
taurus [48]2 years ago
7 0

Answer:

Y axis is vertical the one running up and down in the middle x axis is the one going side to side

Step-by-step explanation:

Whatever it is your asking I hope this helps

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what would be the resulting difference if the line transition: width 2s, height 2s; was removed from the first css rule?
Mkey [24]

Answer:

ages would no longer get larger as the mouse hovers over them. The transition would happen over 10s, since this is the default duration.

Step-by-step explanation:

8 0
2 years ago
Are these arithmetic sequences:
VladimirAG [237]

Answer:

1. No

2. Yes

3. Yes

4. Yes

Step-by-step explanation:

In 1. the difference between each term is not constant.(it goes up by, 2, 4, 6)

2. The terms increase by the same amount(it all goes up by 3)

3. The terms decrease by the same amount(it all goes down by 5)

4. The terms increase by the same amount(it all goes up by 6)

8 0
3 years ago
PLLLLLSSSS Heeeellppp ill mark brainliest I promisseeeeeeee plsssss
WARRIOR [948]

Answer:

2\,(x-1)^2=4

which is the first option in the list of possible answers.

Step-by-step explanation:

Recall that the minimum of a parabola generated by a quadratic expression is at the vertex of the parabola, and the formula for the vertex of a quadratic of the general form:

y=ax^2+bx+c

is at   x_{vertex}=\frac{-b}{2\,a}

For our case, where a=2\,\,, b=-4\,\,,\,\,and \,\,c=-2  we have:

x_{vertex}=\frac{-b}{2\,a}\\x_{vertex}=\frac{4}{2\,*\,2}\\x_{vertex}=1

And when x = 1, the value of "y" is:

y(x)=2x^2-4x-2\\y(1)=2(1)^2-4(1)-2\\y(1)=2-6\\y(1)=-4\\y_{vertex}=-4

Recall now that we can write the quadratic in what is called: "vertex form" using the coordinates (x_{vertex},y_{vertex)of the vertex as follows:

y-y_{vertex}=a\,(x-x_{vertex})^2

Then, for our case:

y-(-4)=2\,(x-1)^2\\y=2\,(x-1)^2-4

Then, for the quadratic equal to zero as requested in the problem, we have:

y=2\,(x-1)^2-4=0\\2\,(x-1)^2-4=0\\2\,(x-1)^2=4

5 0
3 years ago
Which mathematical concept did you use to find the number of gumballs that fit INSIDE the package?
Vlada [557]
The answer is Volume
5 0
2 years ago
What are the solutions to the following system of equations? y = x2 + 3x − 7 3x − y = −2 (2 points) (3, 11) and (−3, −7) (11, 3)
Minchanka [31]
ANSWER

(3, 11) and (−3, −7)


EXPLANATION

The given system of equations are:


y =  {x}^{2}  + 3x - 7

and

3x - y =  - 2

or

y = 3x  + 2


We equate the two equations to obtain,



{x}^{2}  + 3x - 7 = 3x + 2

We rewrite in standard quadratic form to obtain,

{x}^{2}  + 3x  - 3x - 7 - 2 = 0


This simplifies to

{x}^{2}- 9= 0


We solve for x to obtain,


{x}^{2}  = 9

x =  \pm \sqrt{9}

x =  \pm 3

x = 3 \: or \: x =  - 3

When
x = 3

y = 3(3) + 2 = 11

When x=-3,

y = 3(  - 3) + 2 =  - 7


Therefore the solution for the system is (3, 11) and (−3, −7).
7 0
2 years ago
Read 2 more answers
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