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4 years ago

6

In a random poll taken in 2008, Gallup asked 1006 national adults whether they were baseball fans. 433 of the sample said they w

ere. Construct a 95% confidence interval to estimate the proportion of national adults who are baseball fans.

1 answer:

nexus9112 [7]4 years ago

6 0

Answer:

Step-by-step explanation:

i don't know

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What is 3 hours in a fraction form

Bogdan [553]

Answer:

180/60

1 hour is 60 min and 3 times 60 is 180.

So it’s 180/60

Also 180/60 is 3

Step-by-step explanation:

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4 years ago

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The length of an object is measured as 94.8 centimeters. What is this measurement in scientific notation?

ludmilkaskok [199]

9.48*10^1 is the scientific notation

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3 years ago

Mrs. Clayton was buying treats for her children. She bought $12 worth of cinnamon

sineoko [7]

Answer:

Estimate,... about 40

Step-by-step explanation:

12 + 9 + 8 + 10 = 39

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3 years ago

The correlation between height and weight for a certain breed of plant is found to be 0.75. What percentage of the variability i

WINSTONCH [101]

Answer:

The percentage of the variability in plant weight is NOT explained by height is

$p = 43.75$ %

Step-by-step explanation:

From the question we are told that

The correlation between height and weight is $r = 0.75$

Generally the R-Squared between height and weight is mathematically represented as

$R - square = r^2$

substituting values

$R - square = 0.75^2$

$R - square = 0.563$

This R-Squared tells us the percentage of plant weight is accounted by height

and from the calculation we see that it is 56.3%

Now the percentage of plant weight that is not accounted by height is

$p = 100 - 56.3$

$p = 43.75$ %

3 0

3 years ago

A taxi driver provides service in two zones of a city. Fares picked up in zone A will have destinations in zone A with a probabi

sammy [17]

Answer:

The taxi driver's average profit per trip is 4.4.

Step-by-step explanation:

Probability of fares picked up in zone A with destinations in zone A = 0.6

Probability of fares picked up in zone A with destinations in zone B = 0.4

Probability of fares picked up in zone B with destinations in zone A = 0.3

Probability of fares picked up in zone B with destinations in zone B = 0.7

The driver's expected profit for a trip entirely in zone A = 6

The driver's expected profit for a trip entirely in zone B = 8

The driver's expected profit for a trip involving both zones is 12

The taxi driver's average profit per trip:

zone A with destinations in zone A = 0.6 * 6 = 3.6

zone A with destinations in zone B = 0.4 * 12 = 4.8

zone B with destinations in zone A = 0.3 * 12 = 3.6

zone B with destinations in zone B = 0.7 * 8 = 5.6

Total profit expected for 4 trips = 17.6

Average profit per trip = 4.4 (17.6/4)

7 0

3 years ago