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3 years ago

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according to newton’s 3rd law of motion , the strength of a reaction is _____ the strength of the action force

1 answer:

aleksley [76]3 years ago

3 0

Answer:

Equal

Explanation:

According to Newton's third law of motion, the strength of a reaction is equal and opposite to the strength of the action force.

Newton's third law of motion states that "action and reaction forces are equal in magnitude but opposite in direction".
Therefore, if an object exerts a force of magnitude KN on a body.
The body will in return exert the same amount of force back on the object.
The law gives us an idea that force is paired in their action.

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Find the energy in kJ for an x-ray photon with a frequency of 2.4 × 10^18 1/s.

Ilya [14]

Answer:

15912 × 10∧-19 KJ

Explanation:

Given data;

frequency of photon = 2.4 × 10^18 1/s.

Planck's constant = 6.63 × 10∧-34 j.s

Energy = ?

Formula:

E = h × ν

E = 6.63 × 10∧-34 j.s × 2.4 × 10^18 1/s

E= 15.912 × 10∧-16 j

now we will convert the joule into kilo joule,

E = 15.912 × 10∧-16 j /1000 = 15.912 × 10∧-19 KJ

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What type of chemical reaction is C6H6 + CI2 = C6H5CI + HCI

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for it to be balanced in this case would be " <em>4</em> C6H6 + <em>6</em> CI2 = <em>3</em> C6H5CI + <em>9</em> HCI" therefore it's be a <u>Double Replacement</u>

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3 years ago

John dalton proposed a theory that all matter is made up of individuals particles which cannot be divided. what were those parti

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3 years ago

The isomerization of methylisonitrile to acetonitrileCH3NC(g)→CH3CN(g)is first order in CH3NC . The rate constant for the reacti

lisabon 2012 [21]

Answer:

Option E, Half life = $2.96\times 10^3\ s$

Explanation:

For a first order reaction, rate constant and half-life is related as:

$t_{1/2}=\frac{0.693}{k}$

Where,

$t_{1/2}$ = Half life

k = Rate constant

Rate constant given = $2.34\times 10^{-4}\ s^{-1}$

$t_{1/2}=\frac{0.693}{k}$

$=\frac{0.693}{2.34 \times 10^{-4}}=2.96\times 10^3\ s$

So, the correct option is option E.

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4 years ago

For each of the following cases, identify the order with respect to the reactant, A. Case (A ----> product)

damaskus [11]

Answer:

The answers to the question are

1. 2nd and above order order

2. 2nd order

3. 1/2 order

4. 1st order

5. 0 order

Explanation:

We have $\frac{N}{N_{0} } = e^{-\lambda t}$

1. For nth order reaction half life $t_{\frac{1}{2} }$ ∝ $\frac{1}{[A_{0} ]^{n-1} }$

Therefore for a 0 order reaction increasing concentration of the reactant there will increase $t_{\frac{1}{2} }$

First order reaction is independent [A₀].

Second order reaction [A₀] decrease, increase.

Similarly for a third order reaction

1. 2nd order

2. 2nd order reaction

3. Order of reaction is 1/2.

4. 1st order reaction.

5. Zero order reaction.

5 0

3 years ago