Answer:
300K.
Explanation:
The following data were obtained from the question:
Initial volume (V1) = 300L
Initial temperature (T1) = 200K
Final volume (V2) = 450L
Final temperature (T2) =..?
Since the pressure is constant, the gas is obeying Charles' law.
Using the Charles' law equation, we can obtain the new temperature of the gas as follow:
V1/T1 = V2/T2
300/200 = 450/T2
Cross multiply to express in linear form
300 x T2 = 200 x 450
Divide both side by 300
T2 = (200 x 450)/ 300
T2 = 300K
Therefore, the new temperature of the gas is 300K.
The mass of 0.699 mol of C₆H₁₂O₆ is 126 g.
Mass = 0.699 mol × (180.16 g/1 mol) = 126 g
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