The value of 47-36÷3(5+7-3²) is 11.
Answer:
For 
, x = 2, or x = - 2.
Step-by-step explanation:
Here, the given expression is :
Now, using the ALGEBRAIC IDENTITY:
Comparing this with the above expression, we get
⇒Either (x-2) = 0 , or ( x + 2) = 0
So, if ( x- 2) = 0 ⇒ x = 2
and if ( x + 2) = 0 ⇒ x = -2
Hence, for , x = 2, or x = - 2.
She will pay $640 because....
800(.05)= 40
40x16= 640
Answer: the number of adult tickets sold is 400
the number of student tickets sold is 200
Step-by-step explanation:
Let x represent the number of adult tickets sold at the play.
Let y represent the number of student tickets sold at the play.
Adult tickets to a play cost $1.75 each and student tickets cost $1.25 each. If the income from the play was $1,700, it means that
1.75x + 1.25y = 1700 - - - - - - - - - -1
Suppose there are twice as many student tickets sold as adult tickets. This means that
y = 2x
Substituting y = 2x into equation 1, it becomes
1.75x + 1.25 × 2x = 1700= 1700
1.75y + 2.5y = 1700
4.25y = 1700
y = 1700/4.25 = 400
x = y/2 = 400/2 = 200
First, you need to find the derivative of this function. This is done by multiplying the exponent of the variable by the coefficient, and then reducing the exponent by 1.
f'(x)=3x^2-3
Now, set this function equal to 0 to find x-values of the relative max and min.
0=3x^2-3
0=3(x^2-1)
0=3(x+1)(x-1)
x=-1, 1
To determine which is the max and which is the min, plug in values to f'(x) that are greater than and less than each. We will use -2, 0, 2.
f'(-2)=3(-2)^2-3=3(4)-3=12-3=9
f'(0)=3(0)^2-3=3(0)-3=0-3=-3
f'(2)=3(2)^2=3(4)-3=12-3=9
We examine the sign changes to determine whether it is a max or a min. If the sign goes from + to -, then it is a maximum. If it goes from - to +, it is a minimum. Therefore, x=-1 is a relative maximum and x=1 is a relative miminum.
To determine the values of the relative max and min, plug in the x-values to f(x).
f(-1)=(-1)^3-3(-1)+1=-1+3+1=3
f(1)=(1)^3-3(1)+1=1-3+1=-1
Hope this helps!!
