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Alexandra [31]
3 years ago
12

(due by 9) n-43=5 Solve for n, and show your work

Mathematics
1 answer:
omeli [17]3 years ago
8 0

Answer:

n=48

Step-by-step explanation:

  1. add 48 to both sides to get rid of it
  2. 43+5=48
  3. n=48
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How many seconds are in 35 min
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Pythagorean theorem question:)
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11. The price of a bottle of water at a store decreases from $1.65 to $1.40. Rounded to the nearest
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A. 15.2%

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3 years ago
Please help!
777dan777 [17]

Answer:

\begin{array}{ccc}\text{Radius}&\text{Volume of sphere}&\text{Volume of cylinder}\\&&\\1&\dfrac{4}{3}\pi &2\pi \\&&\\2&\dfrac{32}{3}\pi &16\pi \\&&\\3&36\pi &54\pi \\&&\\4&\dfrac{256}{3}\pi &128\pi \\&&\\5&\dfrac{500}{3}\pi &250\pi\end{array}

Step-by-step explanation:

Use formulas for the volumes:

V_{sphere}=\dfrac{4}{3}\pi r^3,\\ \\V_{cylinder}=\pi r^2h=\pi r^2\cdot 2r=2\pi r^3.

1. When r=1,

V_{sphere}=\dfrac{4}{3}\pi\cdot 1^3=\dfrac{4}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 1^3=2\pi.

2. When r=2,

V_{sphere}=\dfrac{4}{3}\pi\cdot 2^3=\dfrac{32}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 2^3=16\pi.

3. When r=3,

V_{sphere}=\dfrac{4}{3}\pi\cdot 3^3=36\pi,\\ \\V_{cylinder}=2\pi \cdot 3^3=54\pi.

4. When r=4,

V_{sphere}=\dfrac{4}{3}\pi\cdot 4^3=\dfrac{256}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 4^3=128\pi.

5. When r=5,

V_{sphere}=\dfrac{4}{3}\pi\cdot 5^3=\dfrac{500}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 5^3=250\pi.

Note that for all r,

\dfrac{V_{sphere}}{V_{cylinder}}=\dfrac{\frac{4}{3}\pi r^3}{2\pi r^3}=\dfrac{2}{3}.

8 0
3 years ago
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