Factor the following quadratic expression n^2+ 4n-12
1 answer:
Answer:
(n + 6)(n - 2)
Step-by-step explanation:
Given
n² + 4n - 12
Consider the factors of the constant term (- 12) which sum to give the coefficient of the n- term (+ 4)
The factors are + 6 and - 2 , since
6 × - 2 = - 12 and 6 - 2 = + 4
Then
n² + 4n - 12 = (n + 6)(n - 2) ← in factored form
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2/ 3 - (3 - 1) * 3 - 1 = -4
Simplify
= 2/-4
which is
= -2/4
Then simplify again
= -1/2
For the first one,
x = 10.
For the second one,
x = 12
