All categories

3 years ago

Plzz I need help math word problem

Mathematics

1 answer:

bixtya [17]3 years ago

7 0

Answer:

there is 600 seats in the room

Step-by-step explanation:

formula you do 12x 40 then 3x40

You might be interested in

Someone Please help me answer this question.

Mekhanik [1.2K]

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Note ∠ Q is a right angle = 90°

Sum the angles and equate to 180

7b + 14 + 6b + 11 + 90 = 180, that is

13b + 115 = 180 ( subtract 115 from both sides )

13b = 65 ( divide both sides by 13 )

b = 5

Thus

∠ R = 6b + 11 = 6(5) + 11 = 30 + 11 = 41°

∠ S = 7b + 14 = 7(5) + 14 = 35 + 14 = 49°

∠ Q = 90°

6 0

3 years ago

Read 2 more answers

Given that slope = -1 and a point (3,-1), write an equation in slope-intercept form of the line?

Elina [12.6K]

Answer:

Step-by-step explanation:

point-slope equation of the line: y+1 = -(x-3)

rearrange to solve for y:

y+1 = -x+3

y = -x + 2 slope-intercept form

7 0

3 years ago

A 120 lb. person would weigh about 20 lb. on the earth's moon. A 150 lb. person would weigh 28 lb. on Io, a moon of Jupiter. Whi

____ [38]

Answer:

Step-by-step explanation:

Earth's moon makes a person weigh about 1/6 of their Earth weight. Io makes a person weigh more than that, because 1/6 of 150 pounds is 25 pounds.

5 0

4 years ago

State the following numbers correct to the decimal place given 78.333 (2d.p) 0.06045 (4d.p) 288.598 (2d.p) 0.1008 (3d.p)

Alex Ar [27]

78.33 (3 rounds down)

0.0605 (5 rounds up)

288.60 (8 rounds up, but there is a nine, so nine becomes 0 and 5 becomes 6)

0.101 (8 rounds up)

6 0

3 years ago

Given the following hypotheses: H0: μ = 490 H1: μ ≠ 490 A random sample of 15 observations is selected from a normal population.

Elenna [48]

Answer:

We conclude that the population mean is equal to 490.

Step-by-step explanation:

We are given that a random sample of 15 observations is selected from a normal population. The sample mean was 495 and the sample standard deviation 9.

Let $\mu$ = population mean.

So, Null Hypothesis, $H_0$ : $\mu$ = 490 {means that the population mean is equal to 490}

Alternate Hypothesis, $H_A$ : $\mu\neq$ 490 {means that the population mean is different from 490}

The test statistics that will be used here is One-sample t-test statistics because we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_1_4$

where, $\bar X$ = sample mean = 495

s = sample standard deviation = 9

n = sample of observations = 15

So, the test statistics = $\frac{495-490}{\frac{9}{\sqrt{15} } }$ ~ $t_1_4$

= 2.152

The value of t-test statistics is 2.152.

Now, at a 0.01 level of significance, the t table gives a critical value of -2.977 and 2.977 at 14 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as the test statistics will not fall in the rejection region.

Therefore, we conclude that the population mean is equal to 490.

4 0

3 years ago