Using the volume for rectangular prisms, the volume of the chimney is: 216 in.³.
<h3>What is the Volume of a Rectangular Prism?</h3>
The volume of a rectangular prism = (length)(width)(height).
<h3>How to Find the Volume of Composite Shapes?</h3>
The Chimney in Emily's house is a composite solid consisting of two rectangular prism. To find the volume, we have to decompose the figure into two rectangular prisms. Then solve for the volume of each before finding the total volume.
Volume of the bigger rectangular prism = (length)(width)(height) = (4)(4)(12)
Volume of the bigger rectangular prism = 192 in.³
Volume of the smaller rectangular prism = (length)(width)(height) = (4)(2)(3)
Volume of the smaller rectangular prism = 24 in.³
The volume of the chimney = volume of the two rectangular prism
The volume of the chimney = 192 + 24
The volume of the chimney = 216 in.³
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Answer:
lim x->0 (-8+x)/x^2
just plug in x = 0
(-8+0)/0
now this fraction is a negative number divided by 0.
So, it equals -infinity.
The limit value is infact -infinity,
so the given option, "Does Not Exit" is the best choice.
Answer: the answer
Would be D
Step-by-step explanation:
Answer:
The correct answer is A: True
Step-by-step explanation:
Since the log is greater than 1 it is going to increase
Answer:
The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.
Step-by-step explanation:
1). Height of the trees at Yard Works are = 7,9,7,12,5 feet
So mean height of the trees = (7+9+7+12+5)÷5
= 40÷5 =8 feet
Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)
(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10
Therefore standard deviation = (10)/(5) =2
2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9
Now we will calculate the mean deviation of the tress at Grow Station
= ∑║(height of the tree-mean height of the tree)║/(number of trees)
= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)
= (0+2+3+3+2)/5
= 10/5 =2
Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.
