All categories

2 years ago

Tomas makes a balloon sculptures at a circus. In 180 minutes, he uses 253 balloons to make 36 identical balloon sculptures.

1 answer:

7 0

$180\ minutes\ \ \ \rightarrow\ \ \ 252\ balloons\\\\1\ minute\ \ \ \rightarrow\ \ \ x\ balloons\\\\x\cdot 180=1\cdot 252\ \ \ \Rightarrow\ \ \ x= \frac{252}{180}= \frac{36\cdot7}{36\cdot5} = \frac{7}{5} =1.4\\\\Ans.\ \ 1.4\ balloons\ per\ one\ minute.\\\\-----------------\\\\ 1\ minute\ \ \ \rightarrow\ \ \ 1.4\ balloons\\\\10\ minutes\ \ \ \rightarrow\ \ \ x\ balloons\\\\x\cdot 1=10\cdot1.4\\\\x=14\\\\Ans.\ \ 14\ balloons\ per\ 10\ minutes.$

You might be interested in

The number of hours, t, it takes a boat to travel 15 miles upstream is represented

iogann1982 [59]

The equation of c is an illustration of subject of formula

The equation of c in terms of r and t is c = r - 15/t

<h3>How to determine the equation?</h3>

The equation is given as:

t = 15/(r - c)

Cross multiply

t(r - c) = 15

Divide both sides by t

r - c = 15/t

Subtract r from both sides

-c = -r + 15/t

Multiply both sides by -1

c = r - 15/t

Take LCM

$c = \frac{rt - 15}{t}$

Hence, the equation of c in terms of r and t is $c = \frac{rt - 15}{t}$

Read more about subject of formula at:

brainly.com/question/10643782

8 0

1 year ago

Identify the type of function represented by each graph

mario62 [17]

Answer:

13. Linear Function

12. Absolute Value Function

11. Quadratic Function

10. Constant and Linear Function

Step-by-step explanation:

13. This graph is in Slope-Intercept Form, $y = mx + b$ . The equation of this line is $y = x + 1$ .

12. This graph obviously is an Absolute Value graph because it is in the shape of a "V".

11. This graph is in the shape of a parabola, so it is considered "Quadratic".

10. This line is constant because it is a horizontal line, but it is ALSO considered a linear function because it is in the form of $y = mx + b$ , and the equation of this line is $y = -2$ , where you have NO rate of change [slope]. This is what you call horizontal lines, zero slopes.

I am joyous to assist you anytime.

6 0

2 years ago

Please help! Correct answer only, please! Find the product A · A^t A. B. C. D.

Karolina [17]

Answer: choice A

Step-by-step explanation:

the transposed matrix would be

5 3

2 -1

5*5+2*2=29

3*5+2*-1=13

5*3-2*-1=13

3*3+-1*-1=10

which gives us the answer

29 13

13 10

6 0

2 years ago

Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen

SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = $\frac{4!}{1! (4 - 1 )!}$ × $\frac{6!}{2! (6 - 2 )!}$

= $\frac{4!}{(3)!}$ × $\frac{6!}{2! (4)!}$

= $\frac{4.3!}{(3)!}$ × $\frac{6.5.4!}{2! (4)!}$

= $4$ × $\frac{6.5}{2.1! }$

= $4$ × $15$ = 60

Total Number of possibility = ¹⁰C₃ = $\frac{10!}{3! (10-3)!}$

= $\frac{10!}{3! (7)!}$

= $\frac{10.9.8.7!}{3! (7)!}$

= $\frac{10.9.8}{3.2.1!}$

= 120

So, probability = $\frac{60}{120} = \frac{1}{2} = 0.5$

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility = ⁴C₀ × ⁶C₃

= $\frac{4!}{0! (4 - 0)!}$ × $\frac{6!}{3! (6 - 3)!}$

= $\frac{4!}{(4)!}$ × $\frac{6!}{3! (3)!}$

= 1 × $\frac{6.5.4.3!}{3.2.1! (3)!}$

= 1× $\frac{6.5.4}{3.2.1! }$

= 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = $\frac{80}{120} = \frac{8}{12} = 0.66$

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility = ⁴C₂ × ⁶C₁

= $\frac{4!}{2! (4 - 2)!}$ × $\frac{6!}{1! (6 - 1)!}$

= $\frac{4!}{2! (2)!}$ × $\frac{6!}{1! (5)!}$

= $\frac{4.3.2!}{2! (2)!}$ × $\frac{6.5!}{1! (5)!}$

= $\frac{4.3}{2.1!}$ × $\frac{6}{1}$

= 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility = ⁴C₃ × ⁶C₀

= $\frac{4!}{3! (4 - 3)!}$ × $\frac{6!}{0! (6 - 0)!}$

= $\frac{4!}{3! (1)!}$ × $\frac{6!}{(6)!}$

= $\frac{4.3!}{3!}$ × 1

= 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = $\frac{100}{120} = \frac{10}{12} = 0.83$

3 0

2 years ago

What is the minimum value for the function shown in the graph? Enter your answer in the box.

Fudgin [204]

The minimum value is the lowest point of a graphed line. The would be the bottom of the "U" shape.

Looking at the graph you can see that the bottom of the U is touching the horizontal line at x = -5.5, so this would be the minimum value.

The lowest part of the line is at -5.5

5 0

2 years ago

Read 2 more answers