2 years ago

How can you find unknown lengths or widths in an easy way? 30 points!

1 answer:

Nadusha1986 [10]2 years ago

7 0

Since you are in middle school, I will assume simple shapes such as rectangles and squares

area=legnth times width
therefor
width=area/legnth and
legnth=area/width

You might be interested in

Find the range of the function for the given domain: f(x)=2x^2−7 with domain: x = {-4, -2, 0, 3}

-BARSIC- [3]

Answer:

f(x)=2(-4)^2-7

=-8^2-7

= 64-7

=57

7 0

2 years ago

A surveryor wants to know how many shoppers at a mall like to read books. He surveys 100 people coming out of a bookstore at the

bonufazy [111]

Yes it is biased aaaaaaaaaaaaaaaaaaaaaaaaaa

3 0

2 years ago

Read 2 more answers

_____________numbers are located to the right of zero on the ____________ line.

Sav [38]

Positive numbers are located to the right of zero on the number line

3 0

3 years ago

10+10 is the same as 11+11 do you understand?

Inga [223]

Answer:

wow

Step-by-step explanation:

lol idle b Betsey e wet get hectic

3 0

2 years ago

Read 2 more answers

Consider the following.3x + 3y = 8(a) Find y' by implicit differentiation.(b) Solve the equation explicitly for y and differenti

ludmilkaskok [199]

Answer:

a.y'=-1

b.y'=-1

c.Yes

Step-by-step explanation:

We are given that consider a function

$3x+3y=8$

Implicit function: That function is a relation in which dependent variable can not be expressed in terms of independent variable

Explicit function: It is that function in which dependent variable can be expressed in terms of independent variable.

a. $3x+3y=8$

Differentiate w.r.t x then we get

$3+3\frac{dy}{dx}=0$

$3\frac{dy}{dx}=-3$

$\frac{dy}[dx}=\frac{-3}{3}=-1$

$\frac{dy}{dx}=y'=-1$

b. $3x+3y=8$

$3y=8-3x$

$y=\frac{8-3x}{3}$

Differentiate w.r.t x then we get

$\frac{dy}{dx}=\frac{-3}{3}=-1$

$\frac{dy}{dx}=y'=-1$

When we substituting the value of y obtained from part b into a solution of part a then we get

$y'=-1$

Hence, solutions are consistent.

8 0

2 years ago