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kotykmax [81]
3 years ago
11

John is looking for an apartment in the city. He has to make decisions about these choices.

Mathematics
1 answer:
mihalych1998 [28]3 years ago
5 0

Answer:

E

Step-by-step explanation:

E

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Find the median<br> of 38,37,39,41,38,42,48,50,54
zhuklara [117]
Median = 41

hope that helps
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3 years ago
I need help for #3 please! Asap:)
Artemon [7]
Is this multiple choice? I know that a is correct.

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Jim wishes to buy 3 gifts that cost 15 dollars, 9 dollars, and 12 dollars. he has 1/4 of the money he needs, how much more money
Archy [21]
In order to solve this, you have to plug in all of the costs of the gifts and add them, which in all equals $36. since jim only has 1/4 of the money he needs to buy the gifts, you need to divide 36 by 4. this gives you 9, so now you know he has 9 dollars.
and to find out how much more money he needs, you can subtract 9 from 36 which represents a fourth of the required money. the answer is 27, that's how much jim needs in order to buy his gifts.
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3 years ago
What transformation transforms (a, b) to (a, −b) ​?
mash [69]

Answer:

Reflection over the x-axis

Step-by-step explanation:

The transformation rule for a reflection over the x-axis is (x, -y)

4 0
3 years ago
Read 2 more answers
2x - 5y=-15<br> can someone walk me through this?
HACTEHA [7]
The equation given in the question has two unknown variables in the form of "x" and "y". The exact value of "x" and "y" cannot be determined as two equations are needed to get to the exact values of "x" and "y". This equation can definitely be used to show the way for determining the values of "x" in terms of "y"and the value of "y" in terms of "x". Now let us check the equation given.
2x - 5y = - 15
2x = 5y - 15
2x = 5(y - 3)
x = [5(y - 3)]/2
Similarly the way the value of y can be determined in terms of "x" can also be shown.
2x - 5y = - 15
-5y = - 2x - 15
-5y = -(2x + 15)
5y = 2x + 15
y = (2x +15)/5
   = (2x/5) + (15/5)
   = (2x/5) + 3
So the final value of x is [5(y -3)]/2 and the value of y is (2x/5) + 3.
3 0
3 years ago
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