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ohaa [14]
2 years ago
11

Can someone help me pls? Surface area of rectangular prism.

Mathematics
1 answer:
Studentka2010 [4]2 years ago
5 0

Answer: picture see the picture

Step-by-step explanation:

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son4ous [18]
La respuesta es el número 4
6 0
3 years ago
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Serious answers only please !! 20 points as well as brainliest for correct answer!!
Gre4nikov [31]

Answer:

Measure of angle A = 55°.

Step-by-step explanation:

From the picture attached,

\frac{AC}{LN}=\frac{BC}{LM}

\frac{10}{5}=\frac{8}{4}

2 = 2

Corresponding sides of the given triangles ΔACB and ΔNLM are proportional.

Therefore, ΔACB ~ ΔNLM.

m∠A = 180° - (90° + 35°) [By triangle sum theorem]

         = 180° - 125°

         = 55°

Measure of angle A is 55°.

8 0
3 years ago
Read 2 more answers
Our difference is 12. Our product is 81. What are the two numbers.
Delicious77 [7]
16.81665382639196787 x 4.81665382639196787

80.99999999999999982646270300946414412

All you have to do is figure out the rest of the decimal places.  I couldn't go any farther. Good luck! 
7 0
3 years ago
A twelve-foot ladder is leaning against a wall. If the ladder reaches ft high on the wall, what is the angle the ladder forms wi
hichkok12 [17]

This question is incomplete.

Complete Question

A twelve-foot ladder is leaning against a wall. If the ladder reaches eight ft high on the wall, what is the angle the ladder forms with the ground to the nearest degree?*

Answer:

42°

Step-by-step explanation:

From the question, the diagram that is formed is a right angle triangle.

To solve for this, we would be using the trigonometric function of Sine.

sin θ = Opposite side/ Hypotenuse

From the question, we are told that:

12 foot ladder is leaning against a wall = Hypotenuse

The ladder reaches 8ft high on the wall = Opposite side.

Hence,

sin θ = 8ft/12ft

θ = arc sin (8ft/12ft)

= 41.810314896

Approximately to the nearest degree

θ = 42°

Therefore, the angle the ladder forms with the ground to the nearest degree is 42°

3 0
3 years ago
You have 100 cm of string which can be cut in one place (or not cut at all) and then formed into a circle and a square (or just
Ne4ueva [31]

Answer:

44cm for minimum area and 0 for maximum area (circle)

Step-by-step explanation:

Let's C be the circumference of the circle and S be the circumference of the square. If we cut the string into 2 pieces the total circumferences would be the string length 100cm.

S + C  = 100 or S = 100 - C

The side of square is S/4 and radius of the circle is \frac{C}{2\pi}

So the area of the square is

A_S = \frac{S^2}{4^2} = \frac{S^2}{16}

A_C = \pi\frac{C^2}{(2\pi)^2} = \frac{C^2}{4\pi}

Therefore the total area is

A = A_S + A_C = \frac{S^2}{16} + \frac{C^2}{4\pi}

We can substitute 100 - C for S

A = \frac{(100 - C)^2}{16} + \frac{C^2}{4\pi}

A = \frac{100^2 - 200C + C^2}{16} + \frac{C^2}{4\pi}

A = 625 -12.5C + \frac{C^2}{16} + \frac{C^2}{4\pi}

A = 625 -12.5C + C^2(\frac{1}{16} + \frac{1}{4\pi})

To find the maximum and minimum of this, we can take the first derivative and set that to 0

A^{'} = -12.5 + 2C(\frac{1}{16} + \frac{1}{4\pi}) = 0

C(\frac{1}{8} + \frac{1}{2\pi}) = 12.5

C \approx 44 cm

If we take the 2nd derivative:

A^{''} = \frac{1}{8} + \frac{1}{2\pi} > 0

We can see that this is positive, so our cut at 44 cm would yield the minimum area.

The maximum area would be where you not cut anything and use the total string length to use for either square or circle

if C = 100 then A_C = \frac{C^2}{4\pi} = \frac{100^2}{4\pi} = 795.77 cm^2

if S = 100 then A_S = \frac{S^2}{16} = \frac{100^2}{16} = 625 cm^2

So to yield maximum area, you should not cut at all and use the whole string to form a circle

4 0
3 years ago
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