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Oliga [24]
3 years ago
6

A 5-digit combination lock with digits 0-9 can be opened only if a correct combination of digits is chosen. Find the probability

of guessing the correct combination if:
Mathematics
2 answers:
Schach [20]3 years ago
5 0
My best guess is a 1/225 chance in guess the right combination

NemiM [27]3 years ago
5 0
You would have a 5/9 chance
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What is the commutative and associative propertys?
timama [110]

Answer:

<u>Commutative property:</u> states that the order in which we multiply numbers does not change the product.

<u>Associative property:</u> states that you can add or multiply regardless of how the numbers are grouped (aka parenthesis).

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5 0
3 years ago
I need helpppppppppppp
ratelena [41]
The answer to question 3 is D. 15(4a+3). And the answer to question 4 is A. 90. Have a great day
7 0
2 years ago
2x - 10 =28 what is x
Brut [27]

Answer:

x = 19

Step-by-step explanation:

2x - 10 = 28

2x = 38

x = 19

Best of Luck!

5 0
3 years ago
Read 2 more answers
Make n the subject of the formula
kogti [31]

Answer:

\mathsf{ \frac{m + 21}{5} = n }

Step-by-step explanation:

To make "n" the subject of the formula, rearrange the formula so it begins with " n = "

To isolate the variable "n", you need to inverse the other terms on that side of the equation where "n" really is.

=> m = 5n - 21

  • <em>there's</em><em> </em><em>a</em><em> </em><em>"</em><em>-21</em><em>"</em><em> </em><em>next</em><em> </em><em>to</em><em> </em><em>"</em><em>5n</em><em>"</em><em>,</em><em> </em><em>inverse</em><em> </em><em>of</em><em> </em><em>subtraction</em><em> </em><em>is</em><em> </em><em>addition</em><em>,</em><em> </em><em>so</em><em> </em><em>add</em><em> </em><em>21</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>equation</em><em>.</em><em> </em>

=> m + 21 = 5n <u>-</u> <u>21</u> + <u>21</u>

=> m+ 21 = 5n

  • <em>There's</em><em> </em><em>also</em><em> </em><em>a</em><em> </em><em>5</em><em> </em><em>attached</em><em> </em><em>to</em><em> </em><em>n</em><em>,</em><em> </em><em>that</em><em> </em><em>means</em><em> </em><em>the</em><em> </em><em>multiplication</em><em> </em><em>of</em><em> </em><em>n</em><em> </em><em>with</em><em> </em><em>5</em><em>,</em><em> </em><em>the</em><em> </em><em>inverse</em><em> </em><em>of</em><em> </em><em>multiplication</em><em> </em><em>is</em><em> </em><em>division</em><em>,</em><em> </em><em>so</em><em> </em><em>dividing</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>equation</em><em> </em><em>by</em><em> </em><em>5</em>

<em>\mathsf{ \frac{m + 21}{5} = n }</em>

3 0
3 years ago
2^5x=6 rounded to the nearest hundredth
Dominik [7]
I believe it would be 0.52
7 0
3 years ago
Read 2 more answers
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