All categories

2 years ago

-5(x-7)<15 solve for x

Mathematics

1 answer:

Nikolay [14]2 years ago

8 0

Answer: X>4

Step-by-step explanation: use distributive property. -5 times X times -7. Subtract -35 from both sides. +35-35 cancels out. Subtract 35 from 15. Divide -5 from both sides. Edit: omg I just realized I didn’t change the sign!

-5x+35<15

-35<15-35

-5x<15-35

-5x<-20

x>4

You might be interested in

The ratio x : 8 is equivalent to the ratio 8 : x^2. What is the value of x?

dimulka [17.4K]

Answer:

x=1

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Toys-A-Go makes toys at Plant A and Plant B. Plant A needs to make a minimum of 1000 toy dump trucks and fire engines. Plant B n

Citrus2011 [14]

Answer:

88 hours on dump truck

24 hours on fire engine

Minimum cost is $3480

Step-by-step explanation:

D > 0; f >0

Plant A : 10d+5f >100

Plant B: 5d +15f >800

Cost:

C(x,y)+30D+35F

4 0

3 years ago

Read 2 more answers

2+5 is going to be a long one ne

andrew-mc [135]

Answer: 7

Step-by-step explanation: Imagine having 5 chocolate bars and then adding 2, or you could try counting with your fingers. Another method is writing a number line and going plus 2 from five so you can visualize it more.

3 0

3 years ago

Read 2 more answers

Expand and combine like terms.<br> (7b^5 – b^2)^2

KiRa [710]

I got 49b^10-14b^7+b^4

7 0

3 years ago

Chandler Heisinger buys a monthly metro card, which entitles him to unlimited subway travel in New York City, for $81 per month.

ANTONII [103]

Let $r$ be the number of rides Chandler takes in a month. Then the cost with the MetroCard is still $81, but the cost without the MetroCard is $2r$ . So we can set up an equation representing what we want: "The cost with a MetroCard of r rides in a month is less than the cost without a MetroCard." In equations,
$81\ \textless \ 2r \\ r\ \textgreater \ 81/2\ \textgreater \ 40 \\
r \geq 41$
Thus, at a minimum, Chandler must take 41 rides for his MetroCard to be cheaper than not having it.

7 0

3 years ago