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givi [52]
3 years ago
5

Yeah another one ha ha

Mathematics
1 answer:
boyakko [2]3 years ago
5 0

Answer:

16.75 cubic inches

Step-by-step explanation:

<u>Key skills needed: Volume of a cylinder, Volume of a sphere</u>

1) To get the answer to this problem, you need to understand two formulas: The volume of a sphere, and The volume of a cylinder.

  • Volume of a sphere --> V= \frac{4}{3}\pi r^3 (V = volume, and r = radius)
  • Volume of a cylinder --> V = \pi r^2h (V = volume, r = radius,h = height)

These formulas will be needed.

2) In order to solve this problem, we need to find the volumes of both, and the subtract them from one another to find the difference.

3) Let's start by finding the volumes:

  • Cylinder --> V = \pi r^2h            

We have the radius (which is 2) and the height (which is 4)

  • This means we can solve --> V = \pi(2^2)(4)
  • 2 squared is 4, so then it would be --> V = \pi (4)(4)
  • 4 times 4 is 16 so V = 16\pi ---> 16 pi is the same as 50.24 cubic inches (if you use 3.14 as pi).
  • Next is the Sphere--> V = \frac{4}{3}\pi r^3

We have the radius (which is 2) so we can solve

  • V = \frac{4}{3}\pi  (2^3)
  • 2 cubed is 8, so it would be --> V = \frac{4}{3}\pi (8)
  • 8 times 4/3 is 32/3 so --> V = \frac{32}{3}\pi --> which is Around 33.51 cubic  inches

4) Now we have to find the difference, so we do:  

  • 50.24 - 33.51 = 16.74

This means your answer would be 16.75 as that is the closest one.

<em>Hope you understood and have a nice day!! :D</em>

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Step-by-step explanation:

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8 0
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The eleventh term from the end of the AP 14, 19, 24, …………., 264 is
vazorg [7]

Answer:

<h2>The eleventh term of the sequence is 64</h2>

Step-by-step explanation:

The sequence given is an arithmetic sequence

14, 19, 24, …………., 264

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substituting the given values in the formula given;

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Read 2 more answers
4log x-1/2log y+3log z
babymother [125]
Following rules of logs, we can do the following:

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Seeing that the neg. sign signifies division, write this new term - log y^(1/2) as a quotient:

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log ----------------
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Next time, please include the instructions when you present your problem.
Thx.

7 0
3 years ago
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