All categories

3 years ago

I'm unsure how to solve this, if you can please respond asap. Thanks!

Mathematics

1 answer:

Alinara [238K]3 years ago

4 0

Answer:

82.5°

Step-by-step explanation:

This is the case of a isosceles triangle , as you may know in a isosceles triangle , there are two sides of equal length as well as two equal angles.

You know that the sum of angles in a triangle is 180°, therefore it comes to this equation :

15° + 2x = 180°

2x = 165°

x = 82.5°

therefore 82.5° is the correct answer.

You might be interested in

Thulani goes to the library every 7 days. He goes to the market every 4 days

emmasim [6.3K]

Thulani goes to both the library and the market for 5 more times during the year.

Step-by-step explanation:

Thulani goes to the library every 7 days. He goes to the market every 4 days.

We have to calculate the Least Common Multiple (LCM) to analyze the next common day on which he will go to both places.

The factors of 7 are: 1 x 7

The factors of 4 are: 2 x 2

Therefore, the LCM would be = 1 x 7 x 2 x 2

LCM = 28

LCM indicates that Thulani will go to both places on every 28th day.

To calculate the number of times (n) he will go to both places on same day. We can use the formula mentioned below:'

$n = \frac{Number of days}{frequency}$

Here frequency represents the LCM = 28.

The number of days are:

August: 30 (we are excluding 1st August)

September: 30

October: 31

November: 30

December: 31

Total = 152

By putting the values in formula, we get

$n = \frac{152}{28}$

n = 5.42

As, the number of times can only be a whole number. Therefore, Thulani goes to both the library and the market for 5 more times during the year.

Learn more:

The following links have more information

brainly.com/question/12419898

brainly.com/question/12764620

Keywords: LCM, same day

#learnwithBrainly

7 0

3 years ago

Tell me both like what should i say in the sentence please

Black_prince [1.1K]

1 is yes and 2 is no epa

4 0

3 years ago

Which ordered pairs are solutions to the inequality 2x+y>−4?

hichkok12 [17]

we will proceed to resolve each case to determine the solution

we have

$2x+y>-4$

$y>-2x-4$

we know that

If an ordered pair is the solution of the inequality, then it must satisfy the inequality.

case a) $(5,-12)$

Substitute the value of x and y in the inequality

$-12>-2*5-4$

$-12>-14$ ------> is True

therefore

the ordered pair $(5,-12)$ is a solution of the inequality

case b) $(-3,0)$

Substitute the value of x and y in the inequality

$0>-2*-3-4$

$0>2$ ------> is False

therefore

the ordered pair $(-3,0)$ is not a solution of the inequality

case c) $(-1,-1)$

Substitute the value of x and y in the inequality

$-1>-2*-1-4$

$-1>-2$ ------> is True

therefore

the ordered pair $(-1,-1)$ is a solution of the inequality

case d) $(0,1)$

Substitute the value of x and y in the inequality

$1>-2*0-4$

$1>-4$ ------> is True

therefore

the ordered pair $(0,1)$ is a solution of the inequality

case e) $(4,-12)$

Substitute the value of x and y in the inequality

$-12>-2*4-4$

$-12>-12$ ------> is False

therefore

the ordered pair $(4,-12)$ is not a solution of the inequality

Verify

using a graphing tool

see the attached figure

the solution is the shaded area above the line

The points A,C, and D lies on the shaded area, therefore the ordered pairs A,C, and D are solution of the inequality

7 0

3 years ago

Read 2 more answers

A square of side length s lies in a plane perpendicular to a line L. One vertex of the square lies on L. As this square moves a

user100 [1]

Answer:

Part (A) The required volume of the column is $s^2h$ .

Part (B) The volume be $s^2h=\frac{s^2h}{2}+\frac{s^2h}{2}$ .

Step-by-step explanation:

Consider the provided information.

It is given that the we have a square with side length "s" lies in a plane perpendicular to a line L.

Also One vertex of the square lies on L.

Part (A)

Suppose there is a square piece of a paper which is attached with a wire through one corner. As you blow it up it spins around on the wire.

This square moves a distance h along L, and generate a corkscrew-like column with square.

The cross section will remain the same.

So the cross section area of original column and the cross section area of twisted column at each point will be the same.

The volume of the column is the area of square times the height.

This can be written as:

$s^2h$

Hence, the required volume of the column is $s^2h$ .

Part (B) What will the volume be if the square turns twice instead of once?

If the square turns twice instead of once then the volume will remains the same but divide the volume into two equal part.

$s^2h=\frac{s^2h}{2}+\frac{s^2h}{2}$

Hence, the volume be $s^2h=\frac{s^2h}{2}+\frac{s^2h}{2}$ .

5 0

3 years ago

50 point! Look at the picture attached. I will mark brainliest!

worty [1.4K]

Answer:

22°

Step-by-step explanation:

Triangle KJL ≅ Triangle MJL (RHS)

[JL = JL(common), KL = LM(given), angle KLJ = angle MLJ(given)]

we come up to the conclusion that 4x + 6 = 3x + 10

x = 4

∴angle KJL = 4(4) + 6 = 22°

6 0

3 years ago

Read 2 more answers