What is the solution to the pair of simultaneous equations? 2x+y=5. 3x-2y=4
1 answer:
Answer:
(2, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Coordinates (x, y)
- Terms/Coefficients
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
2x + y = 5
3x - 2y = 4
<u>Step 2: Rewrite Systems</u>
<em>Manipulate 1st equation</em>
- [Subtraction Property of Equality] Subtract 2x on both sides: y = 5 - 2x
<u>Step 3: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em> [2nd Equation]: 3x - 2(5 - 2x) = 4
- [Distributive Property] Distribute -2: 3x - 10 + 4x = 4
- [Addition] Combine like terms: 7x - 10 = 4
- [Addition Property of Equality] Add 10 on both sides: 7x = 14
- [Division Property of Equality] Divide 7 on both sides: x = 2
<u>Step 4: Solve for </u><em><u>y</u></em>
- Substitute in <em>x</em> [Modified 1st Equation]: y = 5 - 2(2)
- Multiply: y = 5 - 4
- Subtract: y = 1
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