Answer:
She wants to take unusually of the good and bad games into account
Step-by-step explanation:
Given that a basketball coach keeps track of the points scored per game for all of her players. A trophy is given to the player with the highest mean score at the end of the season.
Mean vs median:
Mean is the arithmetic average of all the entries while median is the middle entry after arranging in ascending order.
Median is not affected by extreme items but mean is very much affected by unusually high or low scores.
Here since the trophy is decided to be given to the highest mean score it is obvious that
She wants to take unusually of the good and bad games into account
Because of this only, mean is taken instead of median.
Answer with Step-by-step explanation:
We are given that
A and B are matrix.
A.We know that for two square matrix A and B
Then, 
Therefore, it is true.
B. det A is the product of diagonal entries in A.
It is not true for all matrix.It is true for upper triangular matrix.
Hence, it is false.
C.
When is a factor of the characteristics polynomial of A then -5 is an eigenvalue of A not 5.
Hence, it is false.
D.An elementary row operation on A does not change the determinant.
It is true because when an elementary operation applied then the value of matrix A does not change.
Answer:
2cm
Step-by-step explanation:
Answer:
v = 6
Step-by-step explanation:
Solve for v:
-8 (8 v + 1) - 2 = -394
-8 (8 v + 1) = -64 v - 8:
-64 v - 8 - 2 = -394
Grouping like terms, -64 v - 8 - 2 = -64 v + (-8 - 2):
-64 v + (-8 - 2) = -394
-8 - 2 = -10:
-10 - 64 v = -394
Add 10 to both sides:
(10 - 10) - 64 v = 10 - 394
10 - 10 = 0:
-64 v = 10 - 394
10 - 394 = -384:
-64 v = -384
Divide both sides of -64 v = -384 by -64:
(-64 v)/(-64) = (-384)/(-64)
(-64)/(-64) = 1:
v = (-384)/(-64)
The gcd of -384 and -64 is -64, so (-384)/(-64) = (-64×6)/(-64×1) = (-64)/(-64)×6 = 6:
Answer: v = 6
Answer:
hey mr dsssssssssssssssssssadsdasdsadsadasdsdsd
