HELP ON #15 PLEASE GIVE ME ANSWER!

A researcher posts an online advertisement offering $25 in exchange for participation in a short study. The researchers accepts

Anarel [89]

In this case, I say the answer is A because most short studies dont create valid samples. It all depends on what the short study was about...

5 0

3 years ago

Solve the equation 2x+1=x-3

Agata [3.3K]

How to solve your problem

Topics: Algebra, Quadratic Equation

2

+

1

=

−

3

2x+1=x-3

2x+1=x−3

Solve

1

Subtract

1

from both sides of the equation

2

+

1

=

−

3

2x+1=x-3

2x+1=x−3

2

+

1

−

1

=

−

3

−

1

2x+1{\color{#c92786}{-1}}=x-3{\color{#c92786}{-1}}

2x+1−1=x−3−1

2

Simplify

Subtract the numbers

2

=

−

4

2x=x-4

2x=x−4

3

Subtract

x

from both sides of the equation

2

=

−

4

2x=x-4

2x=x−4

2

−

=

−

4

−

2x{\color{#c92786}{-x}}=x-4{\color{#c92786}{-x}}

2x−x=x−4−x

4

Simplify

Combine like terms

Multiply by 1

Combine like terms

=

−

4

x=-4

x=−4

Solution

=

−

4

5 0

2 years ago

I need help asapppppp

Murljashka [212]

Answer:

10 is a 11 is d and 12 is c but isnt this cheating tho??

Step-by-step explanation:

4 0

3 years ago

A ride ticket usually costs

weqwewe [10]

Answer: Hope this helps if this is what you want.

$14.25

Step-by-step explanation:

$1.50 = 1 ticket

1.50 * 10 = 15

$15 = 10 tickets

100% - 5% = 95% (0.95)

15 * 0.95 = 14.25

$14.25

7 0

1 year ago

Which of the following equations has the same solutions as the equations 3x+2y=-12

Marianna [84]

B, C, E, F

<h2>Explanation:</h2>

In this problem, we have the following equation of a line written in Standard form:

$3x+2y=-12$

So we need to choose the equations that has the same solutions as this equation. If we multiply each equation by a constant term and find the same solution as the given equation, then they will have the same solution. This is only true fro options B, C, E and F.

Option B.

$-3x-2y= 12 \\ \\ Multiply \ both \ sides \ by \ -1: \\ \\ (-1)(-3x-2y)=(-1)(12) \\ \\ 3x+2y=-12$

So we get the same given equation. This option is valid!

Option D.

$15x+10y= -60 \\ \\ Multiply \ both \ sides \ by \ 1/5: \\ \\ (\frac{1}{5})(15x+10y)=(\frac{1}{5})(-60) \\ \\ 3x+2y=-12$

So we get the same given equation. This option is valid!

Option E.

$6x+2y= -12 \\ \\ Multiply \ both \ sides \ by \ 1/2: \\ \\ (\frac{1}{2})(6x+2y)=(\frac{1}{2})(-24) \\ \\ 3x+2y=-12$

So we get the same given equation. This option is valid!

Option F.

$1.5x+y= -6 \\ \\ Multiply \ both \ sides \ by \ 2: \\ \\ (2)(1.5x+y)=(2)(-6) \\ \\ 3x+2y=-12$

So we get the same given equation. This option is valid!

For the other options, there is no any constant term that multiplies both sides of the equation and gives us the same given equation.

<h2>Learn more:</h2>

About this subject: brainly.com/question/8810210

#LearnWithBrainly

7 0

2 years ago