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nataly862011 [7]
3 years ago
15

If ABC is congruent to CBD, then what is the value of x?

Mathematics
1 answer:
kkurt [141]3 years ago
7 0

Answer: \\ 3x = 75 \\ \Leftrightarrow x = 25

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Consider the function represented by the equation 6q = 3s - 9. Write the equation in function notation, where q is the independe
serg [7]

Answer:

s = 2q + 3

Step-by-step explanation:

A linear function has the form:

● y = mx + b

● y is the output of the function

● x is the variabke that we input

● b is the y-intetcept.

Focus on y and x.

Notice that y depends of the value of x. The value of y changes by changing x. So the value of x controls the output y.

y is dependent but x is not.

■■■■■■■■■■■■■■■■■■■■■■■■■■

● 6q = 3s - 9

We want q to be the independent variable wich means that q will be the input. Therefore s should be the output.

The strategy we are going to follow is separating s in one side alone.

● 6q = 3s - 9

Add 9 to both sides

● 6q + 9 = 3s -9 + 9

● 6q + 9 = 3s

Divide both sides by 3

● (6q + 9)/3 = (3s)/3

● (6q)/3 + 9/3 = s

● s = 2q + 3

So the answer is s = 2q + 3

6 0
3 years ago
I need to know how to solve this question please help!
lorasvet [3.4K]

Answer:

-3

Step-by-step explanation:

log7 (1/343)

log7(7^-3)

-3

3 0
3 years ago
2.1(2.3 + 2.1x) = 11.65 + x. Step by step equation please help
DedPeter [7]

Answer:

x=2

Step-by-step explanation:

2.1(2.3 + 2.1x) = 11.65 + x

Distribute

4.83+4.41x=11.65+x

bring 4.83 over (-)

4.41x=6.82+x

bring x over

4.41x-1(x)=6.82

4.41-1=3.41 so

3.41x=6.82

divide 3.41

x=2

3 0
4 years ago
Find the coordinates of the missing endpoint if m is the midpoint of ab. a(-9, -4) and m(-7, -2.5)
Julli [10]

Answer:

The coordinates of the point b are:

b(x₂, y₂)  = (-5, -1)

Step-by-step explanation:

Given

As m is the midpoint, so

m(x, y) = m (-7, -2.5)

The other point a is given by

a(x₁, y₁) = a(-9, -4)

To determine

We need to determine the coordinates of the point b

= ?

Using the midpoint formula

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

substituting (x, y) = (-7, -2.5), (x₁, y₁) = (-9, -4)

\left(-7,\:-2.5\right)=\left(\frac{x_2+\left(-9\right)}{2},\:\:\frac{y_2+\left(-4\right)}{2}\right)

Thus equvating,

Determining the x-coordinate of b

[x₂ + (-9)] / 2 = -7

x₂ + (-9) = -14

x₂ - 9 = -14

adding 9 to both sides

x₂ - 9 + 9 = -14 + 9

x₂ = -5

Determining the y-coordinate of b

[y₂ + (-4)] / 2 = -2.5

y₂ + (-4) = -2.5(2)

y₂ - 4 = -5

adding 4 to both sides

y₂ - 4 + 4 = -5 + 4

y₂ = -1

Therefore, the coordinates of the point b are:

b(x₂, y₂)  = (-5, -1)

6 0
3 years ago
An object is launched vertically in the air at 36.75 meters per second from a 6-meter-tall platform. Using the projectile motion
nasty-shy [4]
I HAVE THE SAME QUESTION
5 0
3 years ago
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