Arithmetic sequence: a_n=a_1+(n-1)d where: d = common difference between terms; n = term; a_1 = first term of sequence a_n = 3+(n-1)4 = 3+(4n-4) = 4n-1 Therefore, a_50 = 4(50)-1 = 200 - 1 = 199
Answer:
Step-by-step explanation:
1) From AP to PB
we get , from part to part that ,
AP=(1/2)*PB or
PB = 2*AP
2) from part to whole,
AP to AB, we get
AP = (1/3)*AB
or AB = 3*AP
Answer:
Can't see that lol
Step-by-step explanation:
Thanks for the 5 points <3
Answer:
2+8=10
Step-by-step explanation:
