Evaluate tan 332°30' Cos 229°47' and sec(-38°22') HELPPP

Complete the missing parts of the table for the following function

djyliett [7]

Step-by-step explanation:

equation y = $6^{x}$

When x = -1

y = $6^{-1}$ = $\frac{1}{6}$ (Answer)

When x = 0,

y = $6^{0}$ = 1 (Answer)

When x = 3,

y = $6^{3}$ = 216 (Answer)

8 0

4 years ago

I need help with number 4, thank you

LiRa [457]

Answer:

Step-by-step explanation:

In number 4 the given figure is a parallelogram, 

So,

Base of the parallelogram = 14

Height of the parallelogram = 9

Therefore, 

Area of the parallelogram = Base × Height 

= 14 × 9

= 126

Hence, area of figure in question no. 4 is 126 (Ans)

8 0

3 years ago

Craig is constructing weights of different sizes to use in his home gym. One such weight is a solid steel sphere with a radius o

bearhunter [10]

The approximate mass of the spherical weight is 51 pounds

To answer the question, we need to know what the mass of the sphere is

<h3>Mass of the sphere</h3>

The mass of the sphere m = ρV where

ρ = density of steel = 0.284 lb/in³ and
V = volume of sphere = 4πr³/3 where
r = radius of sphere = 3.5 in

So, m = ρV

= ρ4πr³/3

Substituting the values of the variables into the equation, we have

m = ρ4πr³/3

= 0.284 lb/in³ × 4π(3.5 in)³/3

= 0.284 lb/in³ × 4π × 42.875 in³/3

= 48.706π lb/3

= 153.014 lb/3

= 51 lb

The approximate mass of the spherical weight is 51 pounds

Learn more about mass of spherical weight here:

brainly.com/question/12911649

#SPJ1

3 0

2 years ago

In a child's bank are 11 coins that have a value of S1.85. The coins are either

Karo-lina-s [1.5K]

Answer:

The child has 6 dimes and 5 quarters.

Step-by-step explanation:

Let q and d represent the number of quarters and of dimes respectively.

Then q + d = 11 (Equation A), and ($0.25/quarter)q + ($0.10/dime)d = $1.85 (Equation B).

Multiply the 2nd equation by 100 to remove the decimal fractions:

25q + 10d = 185 (Equation C)

Now multiply the 1st equation by -10 to obtain -10q - 10d = -110 (Equation D), and combine this result with Equation C:

-10q - 10d = -110

25q + 10d = 185

--------------------------

15q = 75, and so q = 75/15 = 5.

According to Equation A, q + d = 11. Replacing q with 5, we get:

5 + d = 11, and so d = 6.

The child has 6 dimes and 5 quarters.

4 0

4 years ago

The map shows the location of the airport and a warehouse in a city. Though not displayed on the map, there is also a factory 10

kipiarov [429]

step 1

find the coordinates of the factory

the factory is 104 miles due north of the warehouse

the coordinates of the warehouse are (39,-52)

coordinates of the factory------> (39,-52+104)------> (39,52)

step 2

find the distance warehouse to airport

let

A coordinates of warehouse-------> A( 39,-52)

B coordinates of airport---------> B(-39,52)

C coordinates of factory-------> C(39,52)

distance AB=√[(52+52)²+(-39-39)²]------> distance AB=130 miles

step 3

find the distance airport to factory

B(-39,52)

C(39,52)

distance BC=√[(52-52)²+(39+39)²]-----> distance BC=39 miles

the total number of miles=distance AB+distance BC---> 130+39

the total number of miles=169 miles

Thus the answer is 169

4 0

3 years ago

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Evaluate tan 332°30'Cos 229°47'and sec(-38°22') HELPPP​

Evaluate tan 332°30'Cos 229°47'and sec(-38°22') HELPPP