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3 years ago

If the sum of all the scores is divided by the number of scores, then the _____ has been calculated.

Mathematics

1 answer:

monitta3 years ago

8 0

If the sum of all the scores is divided by the number of scores, then the MEAN has been calculated.

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Angle Addition Crossword

Elena-2011 [213]

Answer:

Step-by-step explanation:

1). m∠AEC = m∠AEB + m∠BEC

= 21° + 37°

= 58°

2). m∠BED = m∠BEC + m∠CED

= 37° + 44°

= 81°

3). m∠IKF = m∠IKH + m∠HKG + m∠GKF

= m∠IKH + m∠HKG + m∠IKH [Since, ∠IKH ≅ ∠GKF]

= 2∠IKH + m∠HKG

103° = 2∠IKH + 41°

2(∠IKH) = 103 - 41

m(∠IKH) = 31°

4). m∠AED = m∠AEB + m∠BEC + m∠CED

= 21° + 37° + 44°

= 102°

5). m∠JKG = 108°

m∠JKG = m∠JKI + m∠IKH + m∠HKG

108° = m∠JKI + 31° + 41°

m∠JKI = 108° - 72°

m∠JKI = 36°

6). m∠HKF = m∠GKF + m∠HKG

= m∠IKH + m∠HKG [Since, m∠GKF = m∠IKH]

= 31° + 41°

= 72°

7). m∠NQO = m∠MQN = 64°

8). m∠JKF = m∠JKI + m∠IKF

= 36° + 103°

= 139°

8). m∠MQO = 2(m∠NQO)

= 2(64)°

= 128°

9). m∠LQO = 156°

m∠LQM = m∠LQO - m∠MQO

= 156° - 128°

= 28°

10. m∠NQP = m∠NQO + m∠OQP

= 64° + m∠LQM [Since ∠OQP ≅ ∠LQM]

= 64° + 28°

= 92°

5 0

3 years ago

Find sin(a+b) if tan(a)=7/24 where a is in the third quadrant

ludmilkaskok [199]

The complete question in the attached figure

we have that
tan a=7/24 a----> III quadrant
cos b=-12/13 b----> II quadrant
sin (a+b)=?

we know that
sin(a + b) = sin(a)cos(b) + cos(a)sin(b<span>)
</span>
step 1
find sin b
sin²b+cos²b=1------> sin²b=1-cos²b----> 1-(144/169)---> 25/169
sin b=5/13------> is positive because b belong to the II quadrant

step 2
Find sin a and cos a
tan a=7/24
tan a=sin a /cos a-------> sin a=tan a*cos a-----> sin a=(7/24)*cos a
sin a=(7/24)*cos a------> sin²a=(49/576)*cos²a-----> equation 1
sin²a=1-cos²a------> equation 2
equals 1 and 2
(49/576)*cos²a=1-cos²a---> cos²a*[1+(49/576)]=1----> cos²a*[625/576]=1
cos²a=576/625------> cos a=-24/25----> is negative because a belong to III quadrant
cos a=-24/25
sin²a=1-cos²a-----> 1-(576/625)----> sin²a=49/625
sin a=-7/25-----> is negative because a belong to III quadrant

step 3
find sin (a+b)
sin(a + b) = sin(a)cos(b) + cos(a)sin(b)
sin a=-7/25
cos a=-24/25
sin b=5/13
cos b=-12/13
so
sin (a+b)=[-7/25]*[-12/13]+[-24/25]*[5/13]----> [84/325]+[-120/325]
sin (a+b)=-36/325

the answer is
sin (a+b)=-36/325

8 0

3 years ago

Find the value of x. O is the center of the circle. Round your answer to the nearest hundredth.

katrin [286]

$x=5.38$ . Correct option C)5.38

<u>Step-by-step explanation:</u>

Here we have , Find the value of x. O is the center of the circle. Round your answer to the nearest hundredth. picture is attached . Let's find out:

In the given figure , Let's draw a line from center to the point where cord of length 8 unit is touching the circle or intersecting or , where this chord finishes . This line is radius of circle and is denoted by x , So now we have a right angle triangle with dimensions as :

$Perpendicular =3.6\\Base=\frac{8}{2}=4\\Hypotenuse=x$

By Pythagoras Theorem ,

$Hypotenuse^2=Perpendicular^2+base^2$

⇒ $x^2=(3.6)^2+(4)^2$

⇒ $x=\sqrt{(3.6)^2+(4)^2}$

⇒ $x=\sqrt{12.96+16}$

⇒ $x=\sqrt{28.96}$

⇒ $x=5.38$

Therefore , $x=5.38$ . Correct option C)5.38

6 0

3 years ago

How much do I spend if I use $20 off coupon on my purchase of $97.43

SVEN [57.7K]

$77.43 I’m pretty sure

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2 years ago

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Please help me with this!

salantis [7]

The original area of a face would be a^2. Now that you added b to the edge, the new area of each face would be (a+b)^2. To find how much the are increased, subtract a^2 from (a+b)^2. $(a+b)^2-(a^2)= a^2+2ab+b^2-(a^2)= 2ab+b^2= b(2a+b)$ So the answer is b(2a+b)

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3 years ago

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