4 years ago

Simplify the expression.

Mathematics

1 answer:

spayn [35]4 years ago

7 0

Answer:

C. $\huge\frac{1}{3x {y}^{2} {z}^{4}}$

Step-by-step explanation:

$(9 {x}^{2} {y}^{4} {z}^{8} )^{ - \frac{1}{2} } \\ \\ = ( {3}^{2} {x}^{2} {y}^{4} {z}^{8} )^{ - \frac{1}{2} } \\ \\ = \frac{1}{( {3}^{2} {x}^{2} {y}^{4} {z}^{8} )^{ \frac{1}{2} }} \\ \\ = \frac{1}{(3x {y}^{2} {z}^{4})^{2 \times \frac{1}{2} } } \\ \\ = \frac{1}{3x {y}^{2} {z}^{4}} \\ \\ \red{ \bold{ \therefore \: (9 {x}^{2} {y}^{4} {z}^{8} )^{ - \frac{1}{2} } = \frac{1}{3x {y}^{2} {z}^{4}} }}\\$

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What is the term of a 7-term geometric series if the first term is -11 the last term is -45,056 and the common ratio is -4

shutvik [7]

I assume you mean to ask how to find the sum of the seven terms?

You have

$a_2=ra_1$
$a_3=ra_2=r^2a_1$
$a_4=ra_3=r^3a_1$
...
$a_7=ra_6=r^6a_1$

So the sum is

$a_1+ra_1+r^2a_1+\cdots+r^6a_1=a_1(1+r+r^2+\cdots+r^6)=a_1\times\dfrac{1-r^7}{1-r}$

You know that $a_1=-11$ and $r=-4$ , so the sum is equal to

$-4\times\dfrac{1-(-4)^7}{1-(-4)}=-13108$