Answer:
x+3y-6=0
Step-by-step explanation:
given eqn is y=3x-2 which is 3x-y-2=0
the eqn of line perpendicular to given eqn is -x+3y+k=0
it passes through (6,4)
-6+3*4+k=0
or,. -6+12+k=0
or, k= -6
therefore, the eqn of line perpendicular to given eqn is x+3y-6=0
Step-by-step explanation:
hope it's helpful for you
PLS REFER THE ABOVE ATTACHMENT
Answer:
![100\pi](https://tex.z-dn.net/?f=100%5Cpi)
Step-by-step explanation:
Step 1: Identity the radius.
Since O is the center of the circle, and C and E lie on the circumference, OC and OE are the radii of the circle and thus,
OC=OE.
Step 2: Consider the rectangle.
All diagonals in a rectangle are congruent so this means
DB= OC ( OC is also a diagonal).
Thus, OC= 10 units.
Step 3: Analyze
So this means OE is also 10 units as well.
Since we know the length of the radius, Use the area of circle,
![\pi {r}^{2}](https://tex.z-dn.net/?f=%5Cpi%20%7Br%7D%5E%7B2%7D%20)
![\pi( {10}^{2} ) = 100\pi](https://tex.z-dn.net/?f=%5Cpi%28%20%7B10%7D%5E%7B2%7D%20%29%20%3D%20100%5Cpi)
So the area of a circle is 100 pi.