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irga5000 [103]
2 years ago
13

Kenji has $600 to spend on exercise classes. Each weight training class(x) costs $20 and each aerobic class(y) costs $15. Write

an inequality for this situation and determine which ordered pair is a solution to the inequality. a. 645-09-08-00-00_files/i0200000.jpg c. 645-09-08-00-00_files/i0200001.jpg b. 645-09-08-00-00_files/i0200002.jpg d. 645-09-08-00-00_files/i0200003.jpg
Mathematics
2 answers:
motikmotik2 years ago
8 0
Where's the file/picture/image ?
Tema [17]2 years ago
4 0
Not sure if any files have what my answer is but.
$600 ➗ ($20x + $15y) =
$120 ➗ ($4x+$3y)
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GIVING OUT 50 POINTS
Anika [276]

<u>Answer</u>:

The area of the parallelogram below is <u>48 </u>square meters.

<u>Explanation</u>:

\sf area \ of \ parallelogram = base * height

<u>Given</u>:

  • base: 6 m
  • height: 8 m

<u>using the formula:</u>

→ base * height

→ 6 * 8

→ 48 m²

4 0
2 years ago
Question 3(Multiple Choice Worth 4 points) (06.06) Which of the following demonstrates the Distributive Property? 3(4a + 2) = 12
storchak [24]

Answer:

12a + 6

Step-by-step explanation:

given 3(4a + 2)

multiply each term in the parenthesis by the 3 outside ( distributive law )

= (3 × 4a ) + (3 × 2 ) = 12a + 6


8 0
2 years ago
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The table represents the function f (x) = 2 x + 1.
Salsk061 [2.6K]

Answer:

C

Step-by-step explanation:

In the table, we are given the points [ (-3, -5), (2, y), (5, 11), (8, 17) ]

We are given the equation [ f(x) = 2x + 1 ] where 2 = slope and 1 = y intercept.

We need to find the value of "y".

y2-y1/x2-x1

y-(-5)/2-(-3) = 2

y+5/5 = 2

y = 5

Best of Luck!

5 0
3 years ago
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MODELING WITH MATHEMATICS The backboard of the basketball hoop forms a right triangle with the supporting rods, as shown. Use th
GREYUIT [131]
I can’t see the numbers. I want to help but can’t see the numbers.
7 0
3 years ago
5. 3x + 5y + 5z =1<br> x - 2y = 5<br> 2x + 4y = 11
lilavasa [31]

Answer:

see explanation

Step-by-step explanation:

Given the 3 equations

3x + 5y + 5z = 1 → (1)

x - 2y = 5 → (2)

2x + 4y = 11 → (3)

Use (2) and (3) to solve for x and y

Multiply (2) by 2

2x - 4y = 10 → (4)

Add (3) and (4) term by term

4x = 21 ( divide both sides by 4 )

x = \frac{21}{4\\}

Substitute this value of x into (3)

2 × \frac{21}{4\\} + 4y = 11

\frac{21}{2\\} + 4y = 11 ( subtract \frac{21}{2\\} from both sides )

4y = \frac{1}{2} ( divide both sides by 4 )

y = \frac{1}{8\\}

Substitute the values of x and y into (1) and solve for z

3 × \frac{21}{4\\} + 5 × \frac{1}{8\\} + 5z = 1

\frac{63}{4} + \frac{5}{8} + 5z = 1

\frac{131}{8} + 5z = 1 ( subtract \frac{131}{8} from both sides )

5z = - \frac{123}{8} ( divide both sides by 5 )

z = - \frac{123}{40}

Solution is

x = \frac{21}{4\\}, y = \frac{1}{8\\}, z = - \frac{123}{40}

3 0
2 years ago
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