Cost of each bags of flour = $2.50
Cost of each bags of butter = $3.75
Solution:
Let f be the bags of flour and b be the pounds of butter.
Cost of 20 bags of flour 16 pound of butter = 110
⇒ 20f + 16b = 110 -------------------- (1)
Cost of 30 bags of flour 12 pound of butter = 120
⇒ 30f + 12b = 120 -------------------- (2)
Equation (1) and (2) are the system of equations.
(2) ⇒ 30f + 12b = 120
Subtract 30f from both sides.
⇒ 12b = 120 – 30f
Divide by 12 on both sides.
-------------------- (3)
Substitute (3) in (1).




Subtract 160 from both sides.

Divide by –20, we get

f = 2.50
Substitute f = 2.5 in equation (3), we get


b = 3.75
Cost of each bags of flour = $2.50
Cost of each bags of butter = $3.75
14 2/3 This is the answer! I know you will get this right buddy!
Answer:
Choice A
Step-by-step explanation:
-88<-75<-71<-51
Mark me brainliest if this helped
Answer:
X = 18
Y = 18
Step-by-step explanation:
first make two equation like
x + y = 36
1180x + 125y = 23490
from equation one we have
y = 36- x
put in second equation
1180x + 125 (36-x) = 23490
1180x + 4500-125x = 23490
1055x = 23490-4500
x = 18990/1055
x = 18
put this x value in equation 1 to find y value
18+ y = 36
y = 36-18
y = 18
Answer:
98
Step-by-step explanation:
Have a great rest of your day:D