Answer:
D,0,2,-2
Step-by-step explanation:
2x^5-3x^3-20x=0
x(2x^4-3x^2-20)=0
x=0
or 2x^4-3x^2-20=0
put x²=t
2t²-3t-20=0
-20×2=-40
8-5=3
8×-5=-40
2t²-(8-5)t-20=0
2t²-8t+5t-20=0
2t(t-4)+5(t-4)=0
(t-4)(2t+5)=0
t=4
x²=4
x=2,-2
t=-5/2
x²=-5/2
it gives imaginary root. so real rational roots are 0,2,-2
Answer: -1/2, 0
Step-by-step explanation:
x=0 , y=2x-5 and y=mx+9 form a right angle. So, y=mx+9 is either perpendicular to x=0 or y=2x-5 because the angle between x=0 and y=2x-5 is not 90 degrees. The product of slopes of perpendicular lines equals to -1.
Thus, m=-1/2 if it is perpendicular to y=2x-5. And y=c, for some constant if it is perpendicular to x=0. So y=0x+9 fits the bill. (m=0, in this case)
Answer:
the answer is c
Step-by-step explanation:
i hope this helps
There is no answer. It is an equation and you can find y by literally following the procedure
Answer:
put it over 100 and x by it
Step-by-step explanation:
