Answer:
AB = 20 tan55°
Step-by-step explanation:
Using the tangent ratio in the right triangle
tan55° = 
= 
= 
( multiply both sides by 20 )
20 tan55° = AB
Point R is the midpoint of FE¯¯¯¯¯ , so the coordinates of point R are (3a, b).
In △DEF , the length of the base, DF¯¯¯¯¯ , is
4a, and the height is 2b, so its area is
1/2×4a×2b = 4ab.
In △QRP , the length of the base, QR¯¯¯¯¯ , is
3a-a = 2a, and the height is b, so its area is 1/2×2a×b = ab .
Comparing the expressions for the areas proves that the area of the triangle created by joining the midpoints of an isosceles triangle is one-fourth the area of the larger isosceles triangle.
Answer:
i think its 16/34
Step-by-step explanation:
Then 1 white, then 3 blue then 1 white
The recursive sequence that would produce the sequence 8,-35,137,… is T(n + 1) = -3 - 4T(n) where T(1) = 8
<h3>How to determine the recursive sequence that would produce the sequence?</h3>
The sequence is given as:
8,-35,137,…
From the above sequence, we can see that:
The next term is the product of the current term and -4 added to -3
i.e.
Next term = -3 + Current term * -4
So, we have:
T(n + 1) = -3 + T(n) * -4
Rewrite as:
T(n + 1) = -3 - 4T(n)
Hence, the recursive sequence that would produce the sequence 8,-35,137,… is T(n + 1) = -3 - 4T(n) where T(1) = 8
Read more about recursive sequence at
brainly.com/question/1275192
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