Answer:
Quantity of heat needed (Q) = 722.753 × 10³
Step-by-step explanation:
According to question,
Mass of water (m) = 40 kg
Change in temperature ( ΔT) = 18°c
specific heat capacity of water = 4200 j kg^-1 k^-1
The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .
So, Heat (Q) = m×s×ΔT
Or, Q = 40 kg × 4200 × 18
or, Q = 3024 × 10³ joule
Hence, Quantity of heat needed (Q) = 3024 × 10³ joule
In calories 4.184 joule = 1 calorie
So, 3024 × 10³ joule = 722.753 × 10³
Answer:
The answer is 1&2
Step-by-step explanation:
1.) and documentary is one of the best resource if you have nothing. but if all else fails talk to a doctor they will help you.
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Answer:
<em>tan 19° = 0.3443</em>
Step-by-step explanation:
<u>Value Of Trigonometric Functions</u>
The value of the tangent of 19° cannot be expressed in exact form, that it, as a function of radicals or known constants as pi.
We need to use a calculator, computer, or similar technology to find the required value. We use a scientific calculator to get:
tan 19° = 0.3443
To the nearest ten-thousandth
Looks like the series is supposed to be
The series telescopes; consider the 
th partial sum of the series,
As 
, the second term converges to 0, leaving us with
3(x-5)=1+(5x+2x)
3x-15=1+7x
-15=1+7x-3x
-15=1+4x
-15-1=1+4x-1
-16=4x
-16/4=4x/4
-4=x
