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umka2103 [35]
2 years ago
6

A taxi company charges a

Mathematics
2 answers:
Nina [5.8K]2 years ago
5 0

Answer:

6.25 I think

Step-by-step explanation:

im not really sure but I wish my answer is right

ratelena [41]2 years ago
4 0
0.25 x 25 = 6.25

6.25 + 5 = 11.25

The answer is $11.25
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A regular pentagonal prism has a volume of 2,850 cubic millimeters. what is the height of the prism? a regular pentagonal prism
zlopas [31]

Answer:

Height = 19mm.

Step-by-step explanation:

Area of a regular polygon =  (A * P) / 2 where A = side / (2 * Tan (π / N)) where, N = Number of sides, A = Apothem,  P = Perimeter.

Here A = 5, P = 5*12 = 60 so

Area  of the base  = (5 * 60) / 2 = 150 mm^2.

Volume = area base * height so

Height = volume / area of base

            = 2850 / 150

            = 19 mm.

5 0
1 year ago
What is the value of L-1.1)?<br> O —2<br> 0 -1<br> 0<br> O 1
Kazeer [188]

Answer:

I do not understand.

Step-by-step explanation:

Please add a picture of explain what it is you want help with.

At this moment I do not understand the question, I am sorry.

7 0
3 years ago
Read 2 more answers
My car travels an average 12.3 km on each litre of petrol. What distance willI travel on 105 litres? *
Jobisdone [24]

Answer:

1291.5km

Step-by-step explanation:

12.3*105=1291.5km

3 0
2 years ago
What is the sum of the numbers in the series? 15 + 11 + 7 + . . . + (–129)
babymother [125]
Using Gauss's method
Total number of terms = [15-(-129)]/4+1=36+1=37
Add
S=15+11+7+....-125-129
S=-129-125-...+7+11+15
--------------------------------
2S=-114-114-114...(37 times)
=>
sum=S=(1/2)*(-114)*37=-2109


Using AP, T(n)=15+11+7+....-129
T(n)=19-4n  => T(1)=15, T(37)=-129
S(n)=(1/2)(37)(T(1)+T(37)=(1/2)37(15-129)=2109
3 0
3 years ago
Pls answer asapppddddddd
kvv77 [185]

Answer:

<em><u>don't </u></em><em><u>know</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

<em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

4 0
2 years ago
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