It’s C one while if her assignment
Answer:
Step-by-step explanation:
p + c = 110
p = c + 100
c + 100 + c = 110
2c + 100 = 110
2c = 110 - 100
2c = 10
c = 10/2
c = 5 .......cost of the phone case
p = c + 100
p = 5 + 100
p = 105 <=== cost of the phone
Step-by-step explanation:
let necklace : x
let earrings : y
x+y=144 -1st eqn
6x+5y=825 -2nd eqn
y=144-X -3rd eqn
substitute eqn into 2nd eqn
6x+5(144-x)= 825
6x +720-5X =825 (expanded)
X = 825-720
X =105
substitute "X=105" into 1st eqn
(105)+y=144
y= 144-105
y=39
1 necklace = 105$
1 pair of earrings = 39$
(to check back: substitute the value into the original eqn)
Answer:
From greatest to least
One and five-sixth rounded to 2
One and StartFraction 7 over 29 rounded to 1
0.16 rounded to 0
Step-by-step explanation:
1+7/29=29+7/29
=36/29
=1.24
Approximately
=1
1+5/6=6+5/6
=11/6
=1.83
Approximately
=2
0.16
Approximately =0
From greatest to least
One and five-sixth rounded to 2
One and StartFraction 7 over 29 rounded to 1
0.16 rounded to 0
32+n=105
32-32+n=105-32
n=73
