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3 years ago

8

Is the first one correct and what are the ages? Thanks

1 answer:

Fantom [35]3 years ago

8 0

Answer:

a = 30°

Step-by-step explanation:

We need to find the value of a.

We know that, a straight line makes an angle of 180°.

In this case,

a+3a+2a = 180

6a = 180

a = 30°

So, the value of a is equal to 30°.

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What is the solution of x^2+x-6/x-7<0 PLEASE HELP ME :( (it’s not the 2nd one i already tried it)

kupik [55]

For x^2+x-6/x-7=0, I think it should be x=~2.59262 or x=~-2.75153 or x=~-0.84108

8 0

3 years ago

Muke is sick with the flu but he still cors to school on monday. He areives at 8am and by 9am (hour 1) muke has already infected

Volgvan

Answer:

$\begin{array}{ccccccccc}{Hours} & {0} & {1} & {2} & {3} & {4}& {5} & {6} & {7} \ \\ {Persons} & {1} & {2} & {4} & {8} & {16}& {32} & {64} & {128} \ \end{array}$

Step-by-step explanation:

Given

See attachment for complete question

Solving (a): Complete the table

Let

$x = hours$

$y = persons$

From the table question, we have:

$(x_1,y_1) = (0,1)$

$(x_2,y_2) = (1,2)$

$(x_3,y_3) = (2,4)$

The pattern follows that, an increment in x by doubles the value of 1.

So, the other values are:

$(x_4,y_4) = (3,8)$

$(x_5,y_5) = (4,16)$

$(x_6,y_6) = (5,32)$

$(x_7,y_7) = (6,64)$

$(x_8,y_8) = (7,128)$

So, the complete table is:

$\begin{array}{ccccccccc}{Hours} & {0} & {1} & {2} & {3} & {4}& {5} & {6} & {7} \ \\ {Persons} & {1} & {2} & {4} & {8} & {16}& {32} & {64} & {128} \ \end{array}$

Solving (b): The graph

The table follows an exponential function:

$y = ab^x$

We have: $(x_1,y_1) = (0,1)$

This gives:

$y = ab^x$

$1 = ab^0$

$b^0 \to 1$

So:

$1 = a*1$

$1 = a$

$a =1$

Also: $(x_5,y_5) = (4,16)$

This gives:

$y = ab^x$

$16 = 1 * b^4$

$16 = b^4$

$16 \to 2^4$

So:

$2^4 = b^4$

Cancel the exponents (4)

$2 =b$

$b = 2$

So, the function $y = ab^x$ is:

$y = 2^x$

<em>See attachment 2 for graph</em>

6 0

3 years ago

Answer this please help needed

klasskru [66]

3.√(27x^9) = (27x^9)^(1/3) = 3x^3

8 0

3 years ago

What's the answer<br> Gggggvgvvcdgjhggghhgggggggvhggggggg

docker41 [41]

When answering things like this do the brackets first, is there are parenthesis in the brackets do those but keep it in the brackets and work regularly after

3 0

3 years ago

Given equation x = 6 + i, w = -1 + 5i and z = 4 - 8i, determine each of the following in the form of a + bi

Temka [501]

Answer:

i) 28 - 30i

ii) 36 + 28i

Step-by-step explanation:

i) x = 6 + i ⇒2x = 2(6 + i) = 12 + 2i

z = 4 - 8i ⇒ 4z = 4(4 - 8i) = 16 - 32i

2x + 4z = (12 + 2i) + (16 - 32i) = 28 - 30i

ii) w = -1 + 5i and z = 4 - 8i

w × z = (-1 + 5i)(4 - 8i) = -4 + 8i + 20i - 40 $i^{2}$ ⇒collect like terms

w × z = -4 + 28i - 40 $i^{2}$

∵ $i^{2}=-1$

∴w × z = -4 + 28i - 40(-1) = -4 + 28i + 40 = 36 + 28i

3 0

2 years ago