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3 years ago

7

A professional cyclist is training for the Tour de France. What was his average speed in kilometers per hour if he rode the 194

kilometers from Laval to Blois in 4.2 hours?

1 answer:

Lisa [10]3 years ago

4 0

Start with the distance equation D=RT, then plug in numbers

194=R x 4.2, so all we have to do is divide 194 by 4.2.

Answer: 46.19 kph

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3 years ago

Which is the best estimate for (8.9x10^8)/(3.3x10^4) written in scientific notation? A. 3x10^2 B. 6x10^2 C. 3x10^4 D. 6x10^4

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What are these answers?

Inessa05 [86]

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PLEASE I need help on these 4 problems you don’t have to do them all but if you can at least do one of them TYSM

Brrunno [24]

Answer:

For right angle triangle,

we use Pythagoras theorem that is:

$c^{2} =a^{2} +b^{2}$

c = $\sqrt{a^{2} +b^{2} }$

For question 1:

c = ?

a = 40

b = 9

putting them in formula,

c = $\sqrt{40^{2} + 9^{2} }$

c = 41

For question 2:

c = ?

a = 12

b = 13

putting them in formula,

c = $\sqrt{12^{2} + 13^{2} }$

c = approximately 17.69181

For question 3:

c = 35

a = 20

b = ?

putting them in formula,

$c^{2} =a^{2} +b^{2}$

$35^{2} = 20^{2} + b^{2}$

1225 = 400 + $b^{2}$

$b^{2}$ = 1225 - 400

$b^{2}$ = 825

$\sqrt{b^{2} } = \sqrt{825}$

b = 5 $\sqrt{33}$

For question 4:

c = 37

a = 20

b = ?

putting them in formula,

$c^{2} =a^{2} +b^{2}$

$37^{2} = 20^{2} + b^{2}$

1369 = 400 + $b^{2}$

$b^{2}$ = 1369 - 400

$b^{2}$ = 969

Taking square root on both sides

b = 31.12

Hope it helps.

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2 years ago