Step-by-step explanation:
ATQ,
Let d be the number of kilograms of dark chocolate she buys and m be the number of kilograms of milk chocolate she buys.
She needs to buy 120 kg of chocolate in total for her next order, and her recipe calls for twice the amount of dark chocolate as milk chocolate.
So,
m = 2d .....(1)
m + d = 120 ...(2)
We can also solve the above equations,
Put m = 2d in equation (2)
2d + d = 120
3d=120
d = 40
Put d = 40 in equation (1)
m = 2(40)
m = 80
Hence, she will need 40 kg of dark chocolate and 80 kg of milk chocolate.
1 m ------------- 0,001 K
5 m -------------- x
x = 5 . 0,001
x = 0,005 kilometers
hope this helps!.
Answer:
5.5
Step-by-step explanation:
2,3,3,4,5,7,8,8,8,10,10,12
The mean of this data is 7.5. So what you are trying to figure out is the mean between 2 and 7. Since that is 3 and 4 it would be 3.5. So 3.5 is the Q1. Now you have to figure out the mean between 8 and 12. That is 9. This is Q3. You have to subtract 9-3.5 and that is the interquartile range. So 5.5 is the answer. I hope that made sense.
Answer:
10 rows with 6 passengers per row
Step-by-step explanation:
Let x be the number of rows and y the number of passengers per row.
Then we can interpret the story as the following two equations:
xy=60
(x+2)(y-1)=60
Solving these two equations:
y=60/x
(x+2)(60/x-1)=60 (substitute y)
60 - x + 120/x - 2 = 60 (multiply by -x)
x² + 2x - 120 = 0 (factor)
(x-10)(x+12) = 0
x = 10
y = 60/10 = 6
and indeed 10 * 6 = 60 and also 12 * 5 = 60
Answer:
y=-2x+5
Step-by-step explanation:
That is the equation ^
