Answer:
when x = 0, the answer is 0
when x = 3, the answer is 24
when x = 4, the answer is 32
Answer:
72.47
Step-by-step explanation:
FV cos 43 = TV
FV (0.73135370161 ) = 53
FV = 72.468 = 72.47
Answer:
Victor runs a small sandwich shop. He decides to start offering bags of chips to his customers. He finds a supplier where he can buy chips for $0.30 per bag. Victor needs to determine how much to charge for the chips at his shop. He does some research by talking to other nearby sandwich shop owners. The table below shows their sales per week for two different prices. (The values are: 150 bags sold, for $1.00 per bag, and 350 bags sold, for $0.50 per bag.) Victor believes that there is a linear relationship between the number of bags sold and the price. Victor wants to price the bags of chips so that he will maximize his profits. Determine the price Victor should charge for a bag of chips. Use the equation P(x)=R(x)-C(x), where P(x) represents profit, R(x) represents revenue, and C(x) represents cost. Each is a function of the number of bags of chips sold, x. Round your answer to the nearest nickel.
Step-by-step explanation:
Victor runs a small sandwich shop. He decides to start offering bags of chips to his customers. He finds a supplier where he can buy chips for $0.30 per bag. Victor needs to determine how much to charge for the chips at his shop. He does some research by talking to other nearby sandwich shop owners. The table below shows their sales per week for two different prices. (The values are: 150 bags sold, for $1.00 per bag, and 350 bags sold, for $0.50 per bag.) Victor believes that there is a linear relationship between the number of bags sold and the price. Victor wants to price the bags of chips so that he will maximize his profits. Determine the price Victor should charge for a bag of chips. Use the equation P(x)=R(x)-C(x), where P(x) represents profit, R(x) represents revenue, and C(x) represents cost. Each is a function of the number of bags of chips sold, x. Round your answer to the nearest nickel.
Answer
school building, so the fourth side does not need Fencing. As shown below, one of the sides has length J.‘ (in meters}. Side along school building E (a) Find a function that gives the area A (I) of the playground {in square meters) in
terms or'x. 2 24(15): 320; - 2.x (b) What side length I gives the maximum area that the playground can have? Side length x : [1] meters (c) What is the maximum area that the playground can have? Maximum area: I: square meters
Step-by-step explanation:
That'd be true only if the value of "s" is the exact same one for both
namely if sec(s) = cos(s)
then solving for "s"
thus
![\bf sec(s)=cos(s)\qquad but\implies sec(\theta)=\cfrac{1}{cos(\theta)} \\\\\\ thus\cfrac{1}{cos(s)}=cos(s)\implies 1=cos^2(s)\implies \pm \sqrt{1}=cos(s) \\\\\\ \pm 1=cos(s)\impliedby \textit{now taking }cos^{-1}\textit{ to both sides} \\\\\\ cos^{-1}(\pm 1)=cos^{-1}[cos(s)]\implies cos^{-1}(\pm 1)=\measuredangle s](https://tex.z-dn.net/?f=%5Cbf%20sec%28s%29%3Dcos%28s%29%5Cqquad%20but%5Cimplies%20sec%28%5Ctheta%29%3D%5Ccfrac%7B1%7D%7Bcos%28%5Ctheta%29%7D%0A%5C%5C%5C%5C%5C%5C%0Athus%5Ccfrac%7B1%7D%7Bcos%28s%29%7D%3Dcos%28s%29%5Cimplies%201%3Dcos%5E2%28s%29%5Cimplies%20%5Cpm%20%5Csqrt%7B1%7D%3Dcos%28s%29%0A%5C%5C%5C%5C%5C%5C%0A%5Cpm%201%3Dcos%28s%29%5Cimpliedby%20%5Ctextit%7Bnow%20taking%20%7Dcos%5E%7B-1%7D%5Ctextit%7B%20to%20both%20sides%7D%0A%5C%5C%5C%5C%5C%5C%0Acos%5E%7B-1%7D%28%5Cpm%201%29%3Dcos%5E%7B-1%7D%5Bcos%28s%29%5D%5Cimplies%20cos%5E%7B-1%7D%28%5Cpm%201%29%3D%5Cmeasuredangle%20s)
