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konstantin123 [22]
3 years ago
7

What does the half-life of a radioisotope represent?

Chemistry
2 answers:
MAVERICK [17]3 years ago
5 0

Answer:

O B. It represents the time it takes for half of the material to decay to a

daughter element.

ohaa [14]3 years ago
4 0

It represents the time it takes for half of the material to decay to a daughter element.

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The rate law for the reaction NH4(aq)+ + NO2(aq)- → H2O(l) + NO2(g) is rate = k [NH4+][NO2-], and the value of k is 2.7*10-4 M-1
dybincka [34]
We are given the rate law, so we can substitute the given values for the rate constant and the concentrations of the reactants to solve for the rate of reaction. Since rate = k [NH4+][NO2-]:
rate = (2.7 x 10^-4 / M-s)(0.050 M)(0.25 M) = 3.375 x 10^-6 M/s
8 0
3 years ago
Read 2 more answers
Someone pleaseeee help me I need it now​
denis23 [38]

Answer:

Personal Question

Explanation:

I wish I could help more, but it's based on your own prior knowledge, desires and experiences. Only you can answer those questions. For the first one, if you know examples of genetic engineering you could write that, or you could define it. For the second one, you could talk about things that interest you. The last one you could talk about the concepts you learned in the lesson and the things you didn't know before the lesson and then learned afterward. You could talk about the methods of genetic manipulation, or just what you learn in the class.

4 0
4 years ago
Students working in lab accidentally spilled 17 l of 3.0 m h2so4 solution. they find a large container of acid neutralizer that
jek_recluse [69]

Answer is: 8568.71 of baking soda.

Balanced chemical reaction: H₂SO₄ + 2NaHCO₃ → Na₂SO₄ + 2CO₂ + 2H₂O.

V(H₂SO₄) = 17 L; volume of the sulfuric acid.

c(H₂SO₄) = 3.0 M, molarity of sulfuric acid.

n(H₂SO₄) = V(H₂SO₄) · c(H₂SO₄).

n(H₂SO₄) = 17 L · 3 mol/L.

n(H₂SO₄) = 51 mol; amount of sulfuric acid.

From balanced chemical reaction: n(H₂SO₄) : n(NaHCO₃) = 1 :2.

n(NaHCO₃) = 2 · 51 mol.

n(NaHCO₃) = 102 mol, amount of baking soda.

m(NaHCO₃) = n(NaHCO₃) · M(NaHCO₃).

m(NaHCO₃) = 102 mol · 84.007 g/mol.

m(NaHCO₃) = 8568.714 g; mass of baking soda.

8 0
3 years ago
When a strong acid is titrated with a strong base using phenolphthalein, the color changes suddenly at the end point. The color
larisa86 [58]

Answer:

Keto - enol tautomerism

Explanation:

Phenolphthalein is an organic molecule (formula: C20H14O4), which is used in to determine the final volume in an acid-base titration, this is, as the molecule changes from one to another color, depending on the Ph of the solution (in acids solution, the molecule remains colorless, while in basics solutions it remains pink)  :

The molecule of phenolphthalein is a week acid, which losses a proton (H+) when it´s in solution: the undissociated molecule is colorless, while the correspondent anion (without a H+) is pink. This may be simplified with the following reaction:

H₃In⁺ ⇄ H₂In (colorless) ⇄ In⁻² (pink) ⇄ In(OH) ⁻³

- When adding a base (for example, NaOH) to phenolphthalein (initially, a colorless solution), molecule losses one H⁺ and we obtain In⁻², which is pink

- When adding an acid, the original structured is recovered, so color turns from pink to colorless

This change color is not only explained with adding an acid or a base, but also with phenolphthalein structure, that leads to a keto-enol tautomerism: as molecule has 2 hydroxyl groups (- OH) and 1 carbonyl group (C = O), compounds with this structure have an equilibrium between both groups:

R1 = C H– OH ⇄  R1 – C = O

With this change, phenolphthalein structure changes and hence, color solution changes as well

4 0
3 years ago
3-ethyl-2-methyl-2-pentene
gayaneshka [121]
See photo for drawing :)

3 0
4 years ago
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