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gladu [14]
3 years ago
12

Which of the following is included in nuclide symbols, but is not strictly necessary for the identification of the nuclide?

Chemistry
1 answer:
kodGreya [7K]3 years ago
5 0

Answer:

c. isotope number

Explanation:

Mass Number is the sum total of mass of protons and neutrons present in the nucleus of an atom.  Generally they are being used in distinguishing isotopes. E.g Carbon - 12, Carbon - 13

Atomic Number is the number of protons. Every single element has it's unique atomic number and can be used in identification purpose. E.g Carbon - 6, Hydrogen - 1.

The correct option is option C. This is the symbol that is not necessary for the identification of a nuclide.

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A gold atom in its neutral state has how many electrons
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D 6) Select True or False.
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true

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How should this combustion reaction be balanced?<br> C5H8+O2 + CO2 + H20
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A target is shielded from a radioactive sample by a sheet of metal. What kind of radiation can pass through the sheet of metal
White raven [17]

Answer:

gamma rays only is the correct answer.

Explanation:

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Alpha particles can be blocked by paper and beta particles can  easily passes through  paper but it cannot pass through aluminum sheet whereas gamma particles are hardest to blocked, gamma particles can be blocked by heavy shielding.

Thus the radiation can pass through sheet of metak and hit the target is only gamma rays.

4 0
3 years ago
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Started: Feb 22 at 92
aliina [53]

Answer:

1272 pound

Explanation:

From the question given above, the following data were obtained:

Pressure (P) = 38 psi

Area (A) = 12 cm by 18 cm

Force (F) =?

Next, we shall determine the area. This can be obtained as follow:

Area (A) = 12 cm by 18 cm

A = 216 cm²

Next, we shall convert 216 cm² to square inch (in²). This can be obtained as follow:

1 cm² = 0.155 in²

Therefore,

216 cm² = 216 cm² × 0.155 in² / 1 cm

216 cm² = 33.48 in²

Finally, we shall determine the force exerted. This can be obtained as follow:

Pressure (P) = 38 psi = 38 lbf/in²

Area (A) = 33.48 in²

Force (F) =?

P = F/A

38 = F / 33.48

Cross multiply

F = 38 × 33.48

F = 1272 pound

Thus, the force exerted is 1272 pound

7 0
3 years ago
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