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Thepotemich [5.8K]
3 years ago
15

Determine the net change in NADHNADH , FADH2FADH2 , and GTPGTP from the passage of two acetyl-SCoA molecules through the citric

acid cycle. Degradation of one molecule of glucose yields two acetyl-SCoA molecules. How many molecules of each of the cofactors are produced when these two acetyl-SCoA molecules pass through the citric acid cycle?
Chemistry
1 answer:
CaHeK987 [17]3 years ago
8 0

Answer:The citric acid cycle is the final common pathway for the aerobic oxidation of fuel molecules. Moreover, as we will see shortly (Section 17.3) and repeatedly elsewhere in our study of biochemistry, the cycle is an important source of building blocks for a host of important biomolecules. As befits its role as the metabolic hub of the cell, entry into the cycle and the rate of the cycle itself are controlled at several stages.

Explanation:

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A sample of gold has a mass of 100 grams and a volume of 5cm^3, calculate the density by dividing the mass by volume
Dafna11 [192]

Answer:

20cm^2

Explanation:

Here, Density= Mass/ Volume

=100/5

= 20 cm^2

7 0
3 years ago
10 Points
slamgirl [31]

Answer:

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Explanation:

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5 0
3 years ago
Type the correct answer in the box. Express your answer to three significant figures. Calcium nitrate reacts with sodium phospha
RoseWind [281]

6.07 grams is the theoretical yield of calcium phosphate (Ca₃(PO₄)₂).

<h3>How we calculate mass from moles?</h3>

Mass of any substance can be calculated by using moles as:

n = W/M, where

W = required mass

M= molar mass

Given chemical reaction is:

3Ca(NO₃)₂ + 2Na₃PO₄ → 6NaNO₃ + Ca₃(PO₄)₂

From the stoichiometry it is clear that:

3 moles of Ca(NO₃)₂ = produce 1 mole of Ca₃(PO₄)₂

Given mass of Ca(NO₃)₂ = 96.1g

Mole of Ca(NO₃)₂ = 96.1g/164g/mol = 0.5859moles

So, 0.5859 moles of Ca(NO₃)₂ = produce 0.5859×1/3 = 0.0196 moles of Ca₃(PO₄)₂

Required mass of Ca₃(PO₄)₂ will be calculated by using moles as:

W = 0.0196mole × 310g/mole = 6.07 grams

Hence, 6.07 grams is the theoretical yield of calcium phosphate.

To know more about moles, visit the below link:

brainly.com/question/15373263

7 0
2 years ago
Consider the following weak acids and their Ka values: Acetic Acid Ka = 1.8×10^−5 Phosphoric Acid Ka = 7.5×10^−3 Hypochlorous Ac
vfiekz [6]

Answer:

a. Phosphoric Acid

b. Acetic Acid

c. Hypochlorous Acid

Explanation:

A buffer works when the pH of this one is in pKa ± 1. That means, to find which buffer system works in some pH you need to find pKa:

pKa = -log Ka

<em>pKa Acetic acid:</em>

-log1.8x10⁻⁵ = 4.74

<em>pKa phosphoric acid:</em>

-log7.5x10⁻³ = 2.12

<em>pKa hypochlorous acid:</em>

-log3.5x10⁻⁸ = 7.46

a. For a pH of 2.8 the best choice is phophoric acid because its effective range is: 1.12 - 3.12 and 2.8 is between these values.

b. pH 4.5. Acetic acid. effective between pH's 3.74 - 5.74

c. pH 7.5. Hypochlorous acid that works between 6.46 and 8.46

7 0
3 years ago
In the relationship between ΔG and K for a given reaction, if ΔG is negative, what is K? K is equal to 0. K is equal to 1. K is
frutty [35]
K is greater than 1. #platolivesmatter
3 0
3 years ago
Read 2 more answers
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