Answer: Let x = the length of a side of the square
a2 + b2 = c2
x2 + x2 = 102
2x2 = 100
x2 = 50
x = √50
x = 5√2 cm
Step-by-step explanation:
Answer:
Equilibrium price P = 200 dollars
equilibrium demand of million e-readers per yer = 2.6 mi/yr
Step-by-step explanation:
Given that;
q = 720/p - 1 million units per year { 60 ≤ p ≤ 400 }
supply q = 0.018p − 1 million units per year (60 ≤ p ≤ 400)
we substitute
720/p - 1 = 0.018p − 1
720/p = 0.018p
720 = 0.018p^2
p^2 = 720/0.018 = 40000
p = sqrt(40000)
p = 200
substitute value of p
q = 0.018(200) − 1
q = 3.6 - 1 = 2.6
Therefore Equilibrium price P = 200 dollars
equilibrium demand of million e-readers per yer = 2.6 mi/yr
Answer:
-4182
Step-by-step explanation:
(24-3)-44-4131-28 subtract the numbers in ( ) first
21-44-4131-28 calculate the difference ( subtract in order now)
Area = (theta/360)* pi * r^2
where theta is the angle of the sector
subs by your givens in the above equation
2.512 = (theta/360) * pi * (4)^2
theta = (2.512 * 360) /(pi*(4)^2)
theta = 18 degree
From points A and B, the distance between which is 1020 mi
The speed of one train was 10 mph greater than the speed of the other one
Let the Speed of first train is x
Speed of second train is x+ 10
Time = 5 hours
Distance = speed * time
Distance traveled by first train = x * 5= 5x
Distance traveled by second train = (x+10) * 5= 5x + 50
the trains had not met yet and were 170 mi apart.
the distance between A and B is 1020 mi, Distance traveled by two trains = 1020 - 170 = 850 miles
Distance traveled by first train + second train = 850
5x + 5x + 50 = 850
10x + 50 = 850
Subtract both sides by 50
10x = 800
x= 80
Speed of first train is 80 miles per hour
Speed of second train is 90 miles per hour
