Question

If y = sin (ax + b), where a & b are constants, which of these is true

Answer 1

Step-by-step explanation:

We have y = sin(ax + b).

=> dy/dx = a * cos(ax + b)

=> d²y/dx² = a[a * -sin(ax + b)] = a² - a * sin(ax + b).

Therefore d²y/dx² = a² - ay,

d²y/dx² - a² + ay = 0.