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3 years ago

Give the lowest common multiple and the highest common factor for each pair of numbers 100 and 132

Mathematics

1 answer:

Alex3 years ago

4 0

Answer:

LCM,

(Least common multiple)

100 and 132 is 3300

The GCF

(Greatest common factor)

100 and 132 is 4

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What is the answer to: Find the first three terms: nth term=3n+4?

11111nata11111 [884]

Answer:

7, 10, 13

Step-by-step explanation:

1) n = 1: 3(1) + 4 = 3 + 4 = 7

2) n = 2: 3(2) + 4 = 6 + 4 = 10

3) n = 3: 3(3) + 4 = 9 + 4 = 13

6 0

3 years ago

Read 2 more answers

Gina's number is 2 more than sara's. the sum of their numbers is 68. what are their numbers?

ikadub [295]

In order to solve this problem, we transform the statements into algebraic expressions. First, we assign the variables.

Let:

x = Gina’s number

y = Sara’s number

For the first equation, we show that Gina’s number is greater than Sara’s number by 2. For the second equation, we show that the sum of both numbers is 68.

(1) x – y = 2

(2) x + y = 68

We add the two expressions, which result in the expression: 2x = 70. Then we divide 70 by 2 to get the value of x. We then have x = 35. Using the second equation, we solve for y = 68-35. This gives y = 33. To summarize, Gina’s number is 35 while Sara’s number is 33.

8 0

3 years ago

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The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took these 100 customer

AlladinOne [14]

Answer:

$4-2.326\frac{1}{\sqrt{100}}=3.767$

$4+2.326\frac{1}{\sqrt{100}}=4.233$

So on this case the 98% confidence interval would be given by (3.767;4.233)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=4$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=1$ represent the population standard deviation

n=100 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.01,0,1)".And we see that $z_{\alpha/2}=2.326$