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Elina [12.6K]
3 years ago
11

Give the lowest common multiple and the highest common factor for each pair of numbers 100 and 132​

Mathematics
1 answer:
Alex3 years ago
4 0

Answer:

LCM,

(Least common multiple)

100 and 132 is 3300

The GCF

(Greatest common factor)

100 and 132 is 4

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Alenkinab [10]

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Step-by-step explanation:

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3 years ago
It’s geometry, help plz
m_a_m_a [10]

Answer:

i think its 18(DONT TRUST ME)

Step-by-step explanatioN:

6 x 3                

5 0
2 years ago
The solid below is dilated by a scale factor of 3. Find the volume of the solid created
Klio2033 [76]

The volume of the solid created upon dilation bythe scale factor of 3 is 5832 units³.

<h3>What is the volume of the dilated solid?</h3>

An image is dilated if the dimensions of the image is resized in a way that does not change the shape of the image. When an image is dilated, it is made larger.

Dimensions of the dilataed solid = 6 x 3 = 18

Volume = 18³ = 5832 units³

To learn more about dilation, please check: brainly.com/question/3457976

3 0
2 years ago
An art history professor assigns letter grades on a test according to the following scheme. A: Top 13% of scores B: Scores below
madam [21]

Answer:

The numerical limits for a B grade are 81 and 89, that is, a score between 81 and 89 gets a B grade.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Scores on the test are normally distributed with a mean of 79.7 and a standard deviation of 8.4.

This means that \mu = 79.7, \sigma = 8.4

B: Scores below the top 13% and above the bottom 56%

So between the 56th percentile and the 100 - 13 = 87th percentile.

56th percentile:

X when Z has a p-value of 0.56, so X when Z = 0.15. Then

Z = \frac{X - \mu}{\sigma}

0.15 = \frac{X - 79.7}{8.4}

X - 79.7 = 0.15*8.4

X = 81

87th percentile:

X when Z has a p-value of 0.87, so X when Z = 1.13.

Z = \frac{X - \mu}{\sigma}

1.13 = \frac{X - 79.7}{8.4}

X - 79.7 = 1.13*8.4

X = 89

The numerical limits for a B grade are 81 and 89, that is, a score between 81 and 89 gets a B grade.

4 0
3 years ago
Write an equation describing the relationship of the given variables. y varies inversely as the cube root of x and when x=125, y
notka56 [123]

Answer:

y = 40 / x^1/3

Step-by-step explanation:

Given that :

y α x^1/3

y = k * 1 / x^1/3

y = k / x^1/3

When x = 125 ; y = 8

8 = k / 125^1/3

Cube root of 125 = 5

8 = k / 5

8 * 5 = k ; k = 40

Hence, expression becomes :

y = 40 / x^1/3

4 0
3 years ago
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