Answer:
Option c, A square matrix
Step-by-step explanation:
Given system of linear equations are



Now to find the type of matrix can be formed by using this system
of equations
From the given system of linear equations we can form a matrix
Let A be a matrix
A matrix can be written by
A=co-efficient of x of 1st linear equation co-efficient of y of 1st linear equation constant of 1st terms linear equation
co-efficient of x of 2st linear equation co-efficient of y of 2st linear equation constant of 2st terms linear equation
co-efficient of x of 3st linear equation co-efficient of y of 3st linear equation constant of 3st terms linear equation 
which is a
matrix.
Therefore A can be written as
A= ![\left[\begin{array}{lll}3&-2&-2\\7&3&26\\-1&-11&46\end{array}\right] 3\times 3](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Blll%7D3%26-2%26-2%5C%5C7%263%2626%5C%5C-1%26-11%2646%5Cend%7Barray%7D%5Cright%5D%203%5Ctimes%203)
Matrix "A" is a
matrix so that it has 3 rows and 3 columns
A square matrix has equal rows and equal columns
Since matrix "A" has equal rows and columns Therefore it must be a square matrix
Therefore the given system of linear equation forms a square matrix
Answer: 7
Step-by-step explanation: The only pattern in this sequence that I can see is addition by 4. Therefore, the 3rd term is 15, the 2nd is 11, the 1st is 7.
Please consider Brainliest.
Answer:
It should be -5/2 for the points (-6,8) (-16,33)
Step-by-step explanation:
Mrs. Benson has 184 math assignments left to grade.
<u>Step-by-step explanation:</u>
Here we have , Mrs. Benson has graded 46 math assignments but has 80% of the assignments left to grade.We need to find Mrs. Benson has how many math assignments left to grade. Let's find out:
Let total Number of math assignments be x , So According to question 46 math assignments are graded & 80% are left i.e.
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Now , Assignments left to grade is :
⇒ 
⇒ 
Therefore , Mrs. Benson has 184 math assignments left to grade.