You know that

1 answer:

7 0

So remember that percent means parts out of 100 so
52%=52/100=0.52

26%=26/100=0.26
'of' means multily

0.52 times x=65
divide both sides by 00.52
x=125

26% of a number is 39
0.26 times y=39
divide both sides by 0.26
y=150

x=125
y=150
y is greater

you know that becuase we know that 52% is exatly twice of 26% so therefor, if x=y then 52% of x is half of 26% of y so to compare them, we just divide the 65 number by 2 to find 26% of that number to get 65/2=32.5
32.5<39 so x is smaller number

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The volume of the smoothies served is 18.67 liters.

Given:
volume of fruit juice = 35 liters
ratio of fruit juice to smoothies = 4.5 to 2.4

Proportion: a:b = c:d where ad = bc
a = 4.5 ; b = 2.4 ; c = 35 ; d = x

4.5 to 2.4 = 35 to x

4.5x = 35 * 2.4
4.5x = 84
4.5x/4.5 = 84/4.5
x = 18.67 volume of smoothies.

to check:
4.5(18.67) = 35*2.4
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A system has one each of two different types of components in joint operation. Let X and Y denote the random lengths of the live

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Answer:

The value of E(Y/X) is 2.

Step-by-step explanation:

As the complete question is not given, thus the complete question is found online and is attached herewith.

So the joint density function is given as

$f(x,y)=\left \{ {{\dfrac{x}{8}e^{-\dfrac{x+y}{2}} \,\,\,\,0 \leq x,0\leq y \atop {0}} \right.$

So the marginal function for X is given as

$f_x=\int\limits^{\infty}_0 {f(x,y)} \, dy\\f_x=\int\limits^{\infty}_0 \dfrac{x}{8}e^{-\frac{x+y}{2} }dy\\f_x=\int\limits^{\infty}_0 \dfrac{x}{8}e^{-\frac{x}{2}}e^{-\frac{y}{2} }dy\\f_x= \dfrac{x}{8}e^{-\frac{x}{2}}\int\limits^{\infty}_0e^{-\frac{y}{2} }dy\\f_x= \dfrac{x}{4}e^{-\frac{x}{2}}$

Now

$f(Y/X)=\dfrac{f(X,Y)}{f(X)}\\f(Y/X)=\dfrac{\dfrac{x}{8}e^{-\frac{x+y}{2} }}{\dfrac{x}{4}e^{-\frac{x}{2}}}\\f(Y/X)=\dfrac{1}{2}e^{-\frac{y}{2} }$

Now the value of E(Y/X) is given as

$E(Y/X)=\int\limits^{\infty}_0 {yf_{Y/X}} \, dy \\E(Y/X)=\int\limits^{\infty}_0 {y\dfrac{1}{2}e^{-\frac{y}{2} } }\, dy\\E(Y/X)=\dfrac{1}{2}\dfrac{\sqrt{2}}{(\dfrac{1}{2})^2}=2$